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frosja888 [35]
4 years ago
14

-2 (x-5)=-5x-2 solve the equation.

Mathematics
1 answer:
Vladimir79 [104]4 years ago
5 0
-2x+10=-5x-2
-2x+5x=-2-10
3x=-12
x=-12/3
x=-4
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Which equation shows 6(x + 4) = 2( y + 5) solved for y? A. y = x + 3 B. y = 3x + 5 C. y = 3x + 7 D. y = 3x + 17
UNO [17]

Answer:

C

Step-by-step explanation:

Given

6(x + 4) = 2(y + 5) ← distribute parenthesis on both sides of the equation

6x + 24 = 2y + 10 ( subtract 10 from both sides )

6x + 14 = 2y ( divide all terms by 2 )

3x + 7 = y, hence

y = 3x + 7 → C

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3 years ago
How many models of 100 do you need to model 3200 explain ​
rusak2 [61]

32 models need to make model of 3200.

Given that a 1 model contain 100.

Two series of numbers, usually empirical data, that are proportional or proportional if their respective elements are in constant proportion, called the scaling factor or the rate constant.

One model has 100 elements.

Now, we have to find how many model contains 3200 elements.

So, 1 model=100 elements

n model =3200 elements

We will write this in proportion as

1/n=100/3200

Applying the cross multiply, we get

3200×1=n×100

Divide both sides with 100, we get

3200/100=100n/100

3200/100=n

32=n

Hence, the  32 models contain 3200 elements when one contain 100 elements.

Learn more about proportional from here brainly.com/question/23536327

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4 0
2 years ago
EMERGENCY <br> Triangles ABC and DEF are similar. Find the length of the segments EF and DF
Gala2k [10]

Answer:

EF = 1.5. DF = 2.

Step-by-step explanation:

DE is half of AB so EF is half of BC and DF is half of AC.

7 0
3 years ago
How to round to the nearest 1000 even if there is no thousands in the number given​
Katen [24]

Answer:

To round a number to the nearest 1000, look at the hundreds digit. If the hundreds digit is 5 or more, round up. If the hundreds digit is 4 or less, round down

3 0
3 years ago
Please answer I’ll rate brainlyest
12345 [234]

Answer:

5P3*6C4=60*15=900

Step-by-step explanation:

5P3 refers to the permutations of 5 items taken 3 at a time. To evaluate this, we use factorials as follows;

5P3=\frac{5!}{(5-3)!}

The factorial of an integer n is evaluated as;

n!=n*(n-1)*(n-2)*(n-3).......3*2*1

Using this concept, the above expression can now be simplified as follows;

5P3=\frac{5!}{2!}=\frac{5*4*3*2!}{2!}=5*4*3=60

Therefore, the permutations of 5 items taken 3 at a time is 60.

The next expression, 6C4 refers to the combinations of 6 items taken 4 at a time. The simplification utilizes similar concepts of permutations since we shall be involving factorials;

6C4=\frac{6!}{4!(6-4)!}=\frac{6!}{4!*2!}=\frac{6*5*4!}{4!*2*1}=\frac{6*5}{2*1}=15

Therefore, the combinations of 6 items taken 4 at a time is 15.

The final step is to evaluate the product;

5P3*6C4=60*15=900

3 0
3 years ago
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