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Dima020 [189]
4 years ago
7

Find the smallest whole number by which 396 should be divided so as to get a perfect square numberPLS FAST ...............

Mathematics
2 answers:
Reil [10]4 years ago
5 0

Answer:

Step-by-step explanation:

Prime factorize 396

396  = 3 * 3 * 2 * 2 * 11

       = 3² * 2² * 11

So, to make 396 a perfect square, divide 396 by 11

396÷11 = 36 is a perfect square

emmainna [20.7K]4 years ago
4 0

Answer:

11

Steps:

Find the prime factores of 396.

These are 2x2x3x3x11.

Circle all the pairs and pick out the one that does not have a pair. In this case it is 11.

You can either multiply 396 by 11 or divide by 11 to make it a perfect square.

Since the question asks for divide. It’s 11

Hope this helps.

Good Luck

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2/5of a number is 80. What is 34of the same number?
Masja [62]

Answer:

150

Step-by-step explanation:

First you have to find what number 80 is 2/5 of, to do this do the reciprocal of 2/5 which would be 5/2. Multiply 80 by 5/2 and you'll get 200, then find what 3/4 of 200. Multiply 200 by 3, then divide by 4 to get the answer of 150.

3 0
3 years ago
How do I Factor -12 out of -24k + 120
Juli2301 [7.4K]

Answer:

-12(2k-10)

Step-by-step explanation:

You divide each term by -12, and then put -12 outside of the parenthesis. The parenthesis contain the new equation you just created.

4 0
3 years ago
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HEY! HELP PLEASE, ASAP!! THANKS SO MUCH!!!! ​
inysia [295]

Answer: I think its b

Step-by-step explanation:

4 0
3 years ago
Verify sine law by taking triangle in 4 quadrant<br>Explain with figure.<br>​
Ksivusya [100]

Proof of the Law of Sines

The Law of Sines states that for any triangle ABC, with sides a,b,c (see below)

a

 sin  A

=

b

 sin  B

=

c

 sin  C

For more see Law of Sines.

Acute triangles

Draw the altitude h from the vertex A of the triangle

From the definition of the sine function

 sin  B =

h

c

    a n d        sin  C =

h

b

or

h = c  sin  B     a n d       h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Repeat the above, this time with the altitude drawn from point B

Using a similar method it can be shown that in this case

c

 sin  C

=

a

 sin  A

Combining (4) and (5) :

a

 sin  A

=

b

 sin  B

=

c

 sin  C

- Q.E.D

Obtuse Triangles

The proof above requires that we draw two altitudes of the triangle. In the case of obtuse triangles, two of the altitudes are outside the triangle, so we need a slightly different proof. It uses one interior altitude as above, but also one exterior altitude.

First the interior altitude. This is the same as the proof for acute triangles above.

Draw the altitude h from the vertex A of the triangle

 sin  B =

h

c

      a n d          sin  C =

h

b

or

h = c  sin  B       a n d         h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Draw the second altitude h from B. This requires extending the side b:

The angles BAC and BAK are supplementary, so the sine of both are the same.

(see Supplementary angles trig identities)

Angle A is BAC, so

 sin  A =

h

c

or

h = c  sin  A

In the larger triangle CBK

 sin  C =

h

a

or

h = a  sin  C

From (6) and (7) since they are both equal to h

c  sin  A = a  sin  C

Dividing through by sinA then sinC:

a

 sin  A

=

c

 sin  C

Combining (4) and (9):

a

 sin  A

=

b

 sin  B

=

c

 sin  C

7 0
3 years ago
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Natalija [7]

Answer:

A. {−3.5, −2, 1, 2.5}

Step-by-step explanation:

Remember that the range is the possible values for Y in any given function, so in this case, we are given the Y values and we have to solve the function for x:

y=9+6x

6x=y-9

So we just insert the values, the first one being -12.

So since from the options only A has -3.5 as an option that's the correct answer.

hoped this helped! <3

7 0
3 years ago
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