Hello! For ease of calculations, we can identify the time it took for the weight to bounce back to the other direction, then the other, and then back to its original position by looking at the time it took for the weight to change from 0 to 25 to 0 to -25 then back to 0. This is one whole cycle of the weight.
By the time the weight first reached zero, 1.5 seconds has passed. By the third time it got to zero again, 7.5 seconds has passed. Therefore, one whole cycle of the weight is 7.5-1.5 = 6.0 seconds.
ANSWER: One whole cycle of the weight took 6 seconds.
Answer:
Angle Addition Postulate
Step-by-step explanation:
Given:

Prove:

Proof:
1.
- Angle Addition Postulate
2.
- given
3.
- given
4.
- Substitution Property of Equality
5.
- Simplify
An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term
So...
f(x)=mx+b
m=common difference
b=starting point
f(11)=125=11m+b
-
f(1)=5=1m+b
--------
120=10m
Divide both sides by 10
12=m
Your common difference is 12.
Answer:
yes she can
Step-by-step explanation:
yes she can because $20 is great than $18.50
Answer:
The domain and range remain the same.
Step-by-step explanation:
Hi there!
First, we must determine what increasing <em>a</em> by 2 really does to the exponential function.
In f(x)=ab^x, <em>a</em> represents the initial value (y-intercept) of the function while <em>b</em> represents the common ratio for each consecutive value of f(x).
Increasing <em>a</em> by 2 means moving the y-intercept of the function up by 2. If the original function contained the point (0,x), the new function would contain the point (0,x+2).
The domain remains the same; it is still the set of all real x-values. This is true for any exponential function, regardless of any transformations.
The range remains the same as well; for the original function, it would have been
. Because increasing <em>a</em> by 2 does not move the entire function up or down, the range remains the same.
I hope this helps!