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irga5000 [103]
3 years ago
15

Andrew plays on a basketball team. In two games he scored 2/5 of the total number of points his team scored. His team scored 55

points in the first game and 35 points in the second game. What was the number of points Andrew scored in these two games?
18
20
36
90
Mathematics
2 answers:
Anastasy [175]3 years ago
5 0
Andrew scored 36 points in two games
skelet666 [1.2K]3 years ago
4 0

Answer:

36

Step-by-step explanation:

First we need the total number of points scored.

55+35= 90

Then we need to figure out how many points Andrew had.

2/5 of 90 points.

2/5 is .4 or 40%

So we multiply

90(.4) = 36

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Answer:

The equation of the line that passes through the points (0, 3) and (5, -3) is y = -\frac{6}{5}\cdot x +3.

Step-by-step explanation:

From Analytical Geometry we must remember that a line can be formed after knowing two distinct points on Cartesian plane. The equation of the line is described below:

y = m\cdot x + b (Eq. 1)

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

m - Slope, dimensionless.

b - y-Intercept, dimensionless.

If we know that (x_{1},y_{1}) = (0,3) and (x_{2},y_{2})=(5,-3), the following system of linear equations is constructed:

b = 3 (Eq. 2)

5\cdot m + b = -3 (Eq. 3)

The solution of the system is: b = 3, m = -\frac{6}{5}. Hence, we get that equation of the line that passes through the points (0, 3) and (5, -3) is y = -\frac{6}{5}\cdot x +3.

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How to describe the behavior of the f (x) from the left and from the right of vertical asymptote
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Here you go, hope this kinda helps you out :)

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Stephanie opened a savings account with $200.00. Each additional month, the account will increase by 10%. The function f(x)=200
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A rectangular tank has length 4m, width 12m and height 3.5..i. If the tank is filled with water 2/3 of its capacity ,calculate t
ipn [44]

Answer:

The volume of the water in the tank is 112 m³

Step-by-step explanation:

The volume of the rectangular prism V = L × W × H, where

  • L is its length
  • W is its width
  • H is its height

∵ A rectangular tank has a length of 4 m, a width of 12 m, and

   a height of 3.5 m

∴ L = 4 m

∴ W = 12 m

∴ H = 3.5 m

∵ V = L × W × H

∴ The volume of the tank = 4 × 12 × 3.5

∴ The volume of the tank = 168 m³

∵ The tank is filled with water  \frac{2}{3} of its capacity

→ That means the volume of the water is  \frac{2}{3}  the volume of the tank

∵ The volume of the water = \frac{2}{3} the volume of the tank

∴ The volume of the water =  \frac{2}{3} × 168

∴ The volume of the water = 112 m³

∴ The volume of the water in the tank is 112 m³

3 0
3 years ago
The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
=\mathbb P(Z>1.481)\approx0.0693
5 0
3 years ago
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