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3 years ago

6⁷/6⁵how can I work it out??

Mathematics

2 answers:

Ivan3 years ago

7 0

<h3>Solution:</h3>

$\frac{6^{7} }{ {6}^{5} } \\ = {6}^{(7 - 5)} \\ = {6}^{2} \\ = 36$

<h3>Answer:</h3>

<h3>Hope it helps.</h3>

ray4918 here to help

Tatiana [17]3 years ago

5 0

Answer:

6*2 = 36

Step-by-step explanation:

you can minus the powers

7-5 = 2

6*7 / 6*5 = 6*2

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Mean for 16, 12, 13, 22

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Answer:

mean = sum of the terms/total no. of terms

mean = (16+12+13+22)/4

mean = 63/4 or 15.75

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3 years ago

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Each paper clip is 3/4 of an inch long and cost $0.02. Exactly enough paper clips are laid end to end to have a total length of

cupoosta [38]

I believe that the answer is 0.96 cents

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4 years ago

RUDIKE [14]

Answer:

Answer:

For converging lens

object distance u = - 2.0cm

Focal length f = 5.0cm

From lens formula

Size of image = size of object x Magnification

= 2 x .10 = 2.0cm

For diverging lens

object distance u = 140 - 120 = 20 cm

focal length f = -30 cm

frac{1}{v}+\frac{1}{20}=-\frac{1}{30}

v = -12 cm

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3 0

4 years ago

1 and 2 are complementary angles. 1 and 3 are vertical angles. If

Marizza181 [45]

If angle 1 and angle 2 are <u>complementary, </u>then they add up to 90 degrees. We are given that angle 2 equals 52 degrees.

So we subtract and get our answer:

That's NOT the final answer.

The next step is:

Angle 1 and angle 3 are vertical angles.

Vertical angles are congruent.

So if angle 1 is 38, then angle 3 is also 38.

Now, supplementary angles add up to 180 degrees.

So that's the answer:

180-38=142

142 is the supplement of angle 3.

Hope it helps! :)

Answered by

$***ROSALIND***$

8 0

3 years ago

$20000 is invested in an account that earned 6% p.A. Compounding yearly for 3 years. The interest rate then went up to 8% p.A. F

GuDViN [60]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for the first 3 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$20000\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per annum, thus once} \end{array}\dotfill &1\\ t=years\dotfill &3 \end{cases}$

$\bf A=20000\left(1+\frac{0.06}{1}\right)^{1\cdot 3}\implies A=20000(1.06)^3\implies \boxed{A=2382.032} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \textit{Compound Interest Earned Amount \underline{for the next 4 years}}$

$\bf A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2382.032\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per annum, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}$

$\bf A=2382.032\left(1+\frac{0.08}{1}\right)^{1\cdot 4}\implies A=2382.032(1.08)^4\implies \boxed{A\approx 3240.73} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{amount for this period}}{2382.032+3240.73}\implies 5622.762$

4 0

4 years ago

6⁷/6⁵how can I work it out??​

6⁷/6⁵how can I work it out??