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Svet_ta [14]
3 years ago
6

HELP ME PLEASEEEE: thanks so muchhh I WILL MAKE BRAINLIEST PLZZZ

Mathematics
1 answer:
zzz [600]3 years ago
3 0
We can set up an equation using the information the problem provides us: 
p + pq = 4(p - pq) 
<span>p + pq = 4p - 4pq </span>
<span>5pq = 3p </span>
<span>...since pq ≠ 0... </span>
<span>5q = 3 </span>
<span>q has to = 3/5 is required. Therefore, b</span>
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What number should be placed in the box to help complete the division calculation? Long division setup showing an incomplete cal
lianna [129]

Answer:

The unknown value is being subtracted from 226 is 160

Step-by-step explanation:

Long division setup showing an incomplete calculation

  • 16 is in the divisor
  • 3426 is in the dividend
  • 2 hundreds and 1 tens is written in the quotient
  • 3200 is subtracted from 3426 to give 226
  • An unknown value represented by a box is being subtracted from 226

so,

The dividend = 3426

 The divisor = 16

2 hundreds means 200 and 1 tens means 10

∵ The quotient = 200 + 10 + x

∵ Dividend = divisor × quotient

∴ (16 × 200) + (16 × 10) + (16 × x) +remainder  = 3426  

∵ 16 × 200 = 3200

Subtract 3200 from the dividend  

∴ 3426 - 3200 = 226

∵ 16 × 10 = 160

∴ 226- 160 = 66

⇒160is the unknown value

∵ 16 × x = 16x  

∵ 66 - 16x = 0

∴ 66 = 16x

- Divide both sides by 16

∴ x = 4  and remainder = 2

∴ 3426 ÷ 16 = 200 + 10 + 4

∴ 3426 ÷ 16 = 214  

∴ From the steps above the missing number subtracted from

  226 is 160

The unknown value is being subtracted from 226 is 160

3 0
3 years ago
Am i correct pls help
a_sh-v [17]

Answer:

yea ur correct

Step-by-step explanation:

use PhotoMath or something like that to check next time, it'll save a lot of time

6 0
3 years ago
How to write 15,409 in word form
Papessa [141]
Fifteen thousand, four hundred and nine
5 0
3 years ago
Read 2 more answers
In 3a + b - 12 Name The Coefficients. PLZ<br> A) 3<br> B )3 , 1 , 12<br> C) 3, 1<br> D) a , b
lidiya [134]
C. 3, 1 is the answer!
4 0
3 years ago
Read 2 more answers
Solve equation by factoring.
3241004551 [841]

Hi ;-)

x^2+6x-10=30 \ \ /-30\\\\x^2+6x-40=0\\\\a=1, \ b=6, \ c=-40\\\\\Delta=b^2-4ac=6^2-4\cdot1\cdot(-40)=36+160=196\\\\\sqrt{\Delta}=\sqrt{196}=14\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-14}{2}=\boxed{-10}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+14}{2}=\boxed4

8 0
3 years ago
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