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Answer:
Molar concentration of magnesium ions in the final solution is 0.2 M.
Explanation:
c = Concentration of the solution
n = moles of the compound
V = volume of the solution in L
1) Molarity of solution = 0.100 M
Volume of solution = 100.0 mL = 0.1 L
Moles of in 100 mL solution= n
1 mole of magnesium chloride gives 1 mol of magnesium ions and 2 moles of chloride ions.
Then 0.01 moles of magnesium chloride will give:
magnesium ions.
2) Molarity of solution = 0.100 M
Volume of solution = 100.0 mL = 0.1 L
Moles of in 100 mL solution= n'
1 mole of magnesium phosphate gives 3 mol of magnesium ions and 2 moles of phosphate ions.
Then 0.01 moles of magnesium phosphate will give:
magnesium ions.
After mixing both solutions:
Moles of magnesium ions = x + y = 0.01 mol + 0.03 mol = 0.04 mol
Total volume after mixing = 0.1 L + 0.1 L = 0.2 L
Molar concentration of magnesium ions in the final solution: