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Degger [83]
3 years ago
15

A compound is found to contain 26.73 % phosphorus, 12.09 % nitrogen, and 61.18 % chlorine by mass. What is the empirical formula

for this compound
Chemistry
1 answer:
Mrrafil [7]3 years ago
4 0

Answer:

PNCl_2

Explanation:

Hello!

In this case, when determining empirical formulas by knowing the by-mass percent, we first must assume the percentages as masses so we can compute the moles of each element:

n_P=\frac{26.73g}{30.97g/mol}=0.863mol\\\\n_N=\frac{12.09g}{14.01g/mol}=0.863mol\\\\n_C_l=\frac{61.18g}{35.45g/mol}=1.726mol

Now, for the determination of the subscript of each element in the empirical formula, we divide the moles by the fewest moles (P or N):

P=\frac{0.863mol}{0.863mol}=1\\\\N= \frac{0.863mol}{0.863mol}=1\\\\Cl=\frac{1.726mol}{0.863mol}2

Thus, the empirical formula is:

PNCl_2

Regards!

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In tne equation below identify the bronsted lowry acid bronsted lowry base conjugate acid conjugate base
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Answer:

  • <em>Brønsted-Lowry acid: HNO₂</em>
  • <em>Brønsted-Lowry base: NH₃</em>
  • <em>Conjugate acid: NH₄⁺</em>
  • <em>Conjugate base: NO₂⁻</em>

Explanation:

The equation is:

                 HNO_2(aq)+NH_3(aq)\rightarrow NH4^+(aq)  + NO2^-(aq)

<em>Brønsted-Lowry acids</em>  are H⁺ donors.

<em>Brønsted-Lowry bases</em> are H⁺ acceptors.

Thus, on the left side, <em>HNO₂</em> is the acid and <em>NH₃ </em>is the base.

The <em>conjugate acids</em> and <em>conjugate bases</em> are on the right side of the equation.

The <em>conjugate acid</em> is the spieces that is formed after a base accepts the proton; thus it is <em>NH₄⁺</em>. A <em>conjugate acid</em> contains one more H atom and one more + charge than the base that formed it.

The <em>conjugate base</em> is the species that is formed after the acid donates its proton; thus, <em>NO₂⁻</em> is the <em>conjugate base</em>. A <em>conjugate base</em> contains one less H atom and one more - charge than the acid that formed it.

Summarizing:

  • Brønsted-Lowry acid: HNO₂
  • Brønsted-Lowry base: NH₃
  • Conjugate acid: NH₄⁺
  • Conjugate base: NO₂⁻

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