X is less than two
the graph line goes to the left, indicating the value of x is negative/less than two. It’s not equal to since the circle isn’t filled
Answer:
-6
Step-by-step explanation:
h(x) = -3x – 12 becomes h(-2) = -3(-2) – 12 = -6
Answer:
I would say independent but that is me
Step-by-step explanation:
Sorry if it is wrong
Answer:
r = 10
Step-by-step explanation:
You want to find r such that ...
-20 = 60/-6 -r
r = 60/-6 +20 . . . . . add 20+r
r = -10 +20 = 10
_____
If you mean h(x) = 60/(x -r), then the answer is different.
-20 = 60/(-6-r)
-6-r = 60/-20 . . . . . multiply by (-6-r)/(-20)
-r = -3 +6 = 3 . . . . . add 6, simplify
r = -3 . . . . . . . . . . . . multiply by -1
The function will simply get reflected about the y-axis.
Let's approach this through what we know. Since we know that the x values are mirrored, we know that the points in Quadrant I and IV will be reflected over to the negative side, Quadrants II and III, because they simply change in signs.
However, we also know that the function y-values do not change. This is because whatever the x values are don't change the range and y-values of an even function.
To be more specific, if we have an even function, we are most likely dealing with quadratics or variants/transformations of the quadratic function.
If we were to have 2, and -2, and we wanted to plug them into the equation:

, the signs do not change the y-values of the function.
Hence, we know that it ONLY gets reflected across the y-axis.