Answer:
.b. It is one‐half as large as when n = 100.
Step-by-step explanation:
Given that a simple random sample of 100 batteries is selected from a process that produces batteries with a mean lifetime of 32 hours and a standard deviation of 3 hours.
i.e. s = 0.3
we obtain se of sample by dividing std devitation by the square root of sample size
i.e. s= 
when n =100 this = 0.3 and
when n =400 this equals 0.15
We find that when sample size is four times as large as original, std deviation becomes 1/2 of the original
Correction option is
.b. It is one‐half as large as when n = 100.
Answer:
36π
Step-by-step explanation:
d= 6 in
r= d/2=6/2= 3 in
volume of sphere= 4/3πr^3
=4/3 ×π×3^3
=36π in^3
Answer: Option (c) is correct.
68% of the data points lie between 10 and 18.
Step-by-step explanation: Given : a normal distribution with a standard deviation of 4 and a mean of 14
We have to choose the sentence that correctly describes a data set that follows a normal distribution with a standard deviation of 4 and a mean of 14.
Since, given 68% data.
We know mean of data lies in middle.
And standard deviation is distribute equally about the mean that is 50% of values less than the mean and 50% greater than the mean.
So, 68% of data lies
mean - standard deviation = 14 - 4 = 10
mean + standard deviation = 14 + 4 = 18
So, 68% of the data points lie between 10 and 18.
Answer:
141.4
Step-by-step explanation:
Plug the numbers into the formula, V=πr2h, you know that your radius is 3 and your height is 5, so you get V=π(3)2(5), you just then put it in the calculator. You get 141.37, round to the nearest tenth 141.4
I believe that x=9. I used cross multiplication. First, I multiplied 6 by 15. Second, I divided this product of 90 by 10. The quotient is 9.