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d1i1m1o1n [39]
3 years ago
10

Length of driveway , d, is longer than 1 half mile. How do I write inequality answer?

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0

Answer:

d > 1/2 mile

Step-by-step explanation:


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I need help on ratio of x-coordinates and ratio of y-coordinates
ad-work [718]

Answer:

Ratio of x-coordinates:

\frac{-1}{-2}=\frac{1}{2}

\frac{2}{4}=\frac{1}{2}

\frac{2}{4}=\frac{1}{2}

\frac{-2}{-4}=\frac{1}{2}

Ration of y-coordinates:

\frac{2.5}{5}=\frac{1}{2}

\frac{1}{2}=\frac{1}{2}

\frac{-2}{-4}=\frac{1}{2}

\frac{-2}{-4}=\frac{1}{2}

Step-by-step explanation:

The table is asking for the ratio of x-coordinates for each point (A, B, C and D) for both the image and pre-image.  The ratio is the image 'x' or 'y' value ÷ the pre-image 'x' or 'y' value.  Each ratio should be expressed in simplest form and should show the same pattern of dilation, or same scale factor.  In this case, the second figure is 1/2 the size of the original figure.  

5 0
3 years ago
Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below.
agasfer [191]

Answer:

Class Boundary = 1 between the sixth and seventh classes.

Step-by-step explanation:

              Lengths (mm)                   Frequency

1.                  140 - 143                                  1

2.                 144 - 147                                 16

3.                 148 - 151                                 71

4.                 152 - 155                              108

5.                 156 - 159                               83

6.                 160 - 163                                18

7.                  164 - 167                                 3

The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.

Therefore the class boundary between the sixth and seventh classes

= 164 - 163  = 1

Therefore Class Boundary = 1.

It can be seen that class boundary for the frequency distribution is 1.

If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.

Therefore, Class width,

w = lower limit of second class - lower limit of first class

   = 144 - 140

   = 4

7 0
3 years ago
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