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Westkost [7]
2 years ago
11

kassim has amoney box containing 100 mixed sh 5 and sh 10 coins with a totalvalue of sh 600. How many of each type of coin does

the box contain
Mathematics
1 answer:
lukranit [14]2 years ago
3 0

Answer:

sh 5 coins=80

sh 10 coins=20

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Help i hill give brainliest
lina2011 [118]

Answer:

530.66 cm²

Step-by-step explanation:

take half the diameter of 26 and that gives you the radius of 13

A =π· r²

A = 3.14 x 169

8 0
2 years ago
Find 2x2 − 2z4 + y2 − x2 + z4 if x = −4, y = 3, and z = 2 can you help me
Natali [406]
Alright, so plugging it in, we get 2(-4)^2=2(2)^4+3^2-(-4)^2+2^4. Use PEMDAS with parenthesis and exponents to then get (2)(16)+9-16+16. Multiplying 1 and 16,  we get 32+41-16+16=73
8 0
3 years ago
In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.
Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}


In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, B. Then, we can find the third side. Using the law of sines, we can find:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}


We can use this to solve for B:

13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}

B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1


Now, we can find C:

C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}


Using this, we can find c:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}

c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}


c is approximately 17.5.

8 0
3 years ago
Please help me find the total area of the composite figure below (geometry)
Akimi4 [234]

Answer:

lw + \frac{1}{2} × π × (\frac{l}{2} )^{2} ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = \frac{1}{2} × π × r²

<u>Given that,</u>

diameter of the semi-circle is ⇒ <em>l</em>

∴ radius ⇒ <em>l / 2</em>

<u>Let us find it now.</u>

Area = \frac{1}{2} × π × r²

Area =  \frac{1}{2} × π × (\frac{l}{2} )^{2}

<u>                                                     </u>

Secondly, let us find the area of the rectangle.

Area = length × width

<u>Given that,</u>

length ⇒ <em>l</em>

width ⇒ w

<u>Let us find it now.</u>

Area = length × width

Area = l ×w

Area = lw

<u>                                                      </u>

And now let us <u>find the total area.</u>

Total area =  Area of the rectangle + Area of the semi - circle

Tota area = lw + \frac{1}{2} × π × (\frac{l}{2} )^{2}

8 0
2 years ago
Solve for m and n using the special right triangles
Irina18 [472]
Since this is a 45-45-90 triangle, n = 6 and m = 6√3.

I hope this helps!
8 0
3 years ago
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