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Vitek1552 [10]
3 years ago
10

Can I have some robux, I’ll mark you brainlist

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
7 0

Answer:

nope

Step-by-step explanation:

xeze [42]3 years ago
6 0

Answer:

chile anyways so lol ..

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Given r(x) =11/(x-4)^2 which represents a domain restriction on r(x) and the corresponding inverse function?
saul85 [17]

Answer:x>4;r-1(x)=4-(root of (11/x))

Step-by-step explanation:

Edgenuity 2020

6 0
3 years ago
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I NEED HELP! Let me know how you got that answer I’m trying to understand and I’ll mark you brainliest :)
zlopas [31]

Answer:

A- (-1,0) B- (1,7) C- (6,5)

Step-by-step explanation:

these would be your new coordinates

6 0
4 years ago
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Solve the equation 5x+2=62
suter [353]
B. 12
5x = 62-2
5x= 60
x = 60/5
x = 12
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4 years ago
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What is the value of 4*(-1+2-3+4-3+6-7+....+100) Show your work. [Pls help I am really drowning in work. 50 points + brainliest
KengaRu [80]

Answer:

200

Step-by-step explanation:

We have:

4(-1+2-3+4-5+6-7...+100)

We can rearrange the numbers to obtain:

4((-1-3-5-7-...-99)+(2+4+6...+100))

From the left, we can factor out a negative. So:

4(-(1+3+5+7+...+99)+(2+4+6...+100))

In other words, we want to find the sum of all the odd numbers from 1 to 99.

And the sum of all the even numbers from 2 to 100.

Let's do each one individually:

Odd Terms:

We have:

(1+3+5+7+...+99)

We can use the arithmetic series formula, where:

S=\frac{k}{2}(a+x_k)

Where k is the number of terms, a is the first term, and x_k is the last term.

Since it's all the odd numbers between 1 and 99, there are 50 terms.

Our first term is 1 and our last term is 99. So, the sum of all the odd terms are:

S=\frac{50}{2}(1+99})

Divide the fraction. Add within the parentheses:

S=25(100)

Multiply:

S=2500

So, the sum of all the odd terms is 2500.

Even Terms:

We have:

(2+4+6+...+100)

Again, we can use the above formula.

Our first term is 2, last term is 100. And since it's from 2-100, we have 50 even terms. So:

S=\frac{50}{2}(2+100)

Divide and add:

S=25(102)

Multiply:

S=2550

We originally had:

4(-(1+3+5+7+...+99)+(2+4+6...+100))

Substitute them for their respective sums:

4(-(2500)+2550)

Multiply:

4(-2500+2550)

Add:

=4(50)

Multiply:

=200

So, the sum of our sequence is 200.

And we're done!

Note: I just found a <em>way</em> easier way to do this. We have:

4\cdot(-1+2-3+4-5+6-7+...+100)

Let's group every two terms together. So:

=4((-1+2)+(-3+4)+(-5+6)...+(-99+100))

We can see that they each sum to 1:

=4((1)+(1)+(1)+...+(1))

Since there are 100 terms, we will have 50 pairs, so 50 times 1. So:

=4(50)

Multiply:

=200

Pick which one you want to use! I will suggest this one though...

Edit: Typo

8 0
4 years ago
PLEASE HELP!!! I DONT HAVE ENOUGH POINTS TO POST MORE THAN ONCE!
Marat540 [252]

Answer:

-3.

Step-by-step explanation:

In the table, the y value goes down by -4 and then -2, for a total of -6.

We did this over a period of two units (To go from -1 to 1, we add 2).

-6/2 = -3.

-3 is the average rate of change over the interval.

3 0
4 years ago
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