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Citrus2011 [14]
3 years ago
6

If an elevator travels 5 stories every 6 seconds, how many stories does it travel in 24 seconds?

Mathematics
2 answers:
Rufina [12.5K]3 years ago
3 0
Divide 24 by 6 in order to see how many six second intervals there are. 24/6=4. Multiply 4x5 to show many stories the elevator travels. The answer will be 20 stories.
RoseWind [281]3 years ago
3 0
This is 20 storis because you have to do 24 divived by 6 tims 5 
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saw5 [17]
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7 0
3 years ago
8 times the difference of u and 10
koban [17]

Answer: 8(u - 10)

Step-by-step explanation:

8 0
3 years ago
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If 30 buses can carry 1,500 people, how many people can 5 buses carry? A 200 © 500 B 250 D 750​
maksim [4K]

Answer:

\boxed {\boxed {\sf 250 \ people}}

Step-by-step explanation:

Let's set up a proportion using the following setup.

\frac {buses}{people}=\frac {buses}{people}

We know 30 buses can carry 1,500 people.

\frac {30 \ buses}{1500 \ people}=\frac {buses}{people}

We don't know how many people 5 buses can carry, so we say 5 buses carry x people.

\frac {30 \ buses}{1500 \ people}=\frac {5 \ buses}{x \ people}

\frac {30 }{1500 }=\frac {5 }{x }

Cross multiply. Multiply the numerator of the first fraction by the second fraction's denominator. Then, multiply the first denominator by the second numerator.

30*x=1500*5\\30x=7500

Solve for x. It is being multiplied by 30. The inverse of multiplication is division. Divide both sides by 30.

30x/30=7500\\x=250

5 buses can carry 250 people.

7 0
3 years ago
The universal set in this diagram is the set of integers from 1 to 15. place the integers in the correct place in the venn diagr
neonofarm [45]

Answer:


Step-by-step explanation:

Given :  universal set in this diagram is the set of integers from 1 to 15.

Solution :

The intersection of odd integer,multiples of 3 and Factors of 15 are 3,15

The intersection of odd integer and Factors of 15 are 1,5

The intersection of odd integer,multiples of 3 is 9

The remaining multiples of 3 are 6,12

The remaining odd integers are 7,11,13

Now the remaining integers are 2,4,8,10,14 and these integers must be placed in the boxes outside the circles Since they does not belong any intersection or odd integer or factor of 15 .

Refer the attached figure for the answer.

3 0
3 years ago
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tatiyna
You can prove a triangle is isosceles by finding the amount of right angles in a triangle. A triangle containing 2 right angles is classified as isosceles.
8 0
3 years ago
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