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rodikova [14]
2 years ago
11

What is the perimeter of the figure to the nearest tenth of a millimeter?

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
7 0
We have to calculate the perimeter of the figure to the nearest tenth of a millimeter. This figure is made of a rectangle and a half of a circle. The first figure has the perimeter: 3 + 6 + 3 = 12 mm. The second figure has the perimeter: 2 * Pi * r / 2 = Pi * r ; and the radius : r = 6/2 = 3 mm. So Pi * 3 = 3.14 * 3 = 9.42. Fimally : 12 + 9.42 = 21.42 or 21.4 to the nearest tenth. Answer: C. 21.4 millimeters<span>. </span>
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Answer:

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What is the equation of the circle with center (-3,1) that passes through the point (-5, 3)?
Natali5045456 [20]

Answer:

Option B) (x + 3)^2 + (y – 1)^2 = 8 is the correct answer.

Step-by-step explanation:

The equation of a circle with center (h,k) and radius r is given by:

(x-h)^2 + (y-k)^2 = r^2

Given

Center = (h,k) = (-3,1)

=> h = -3

=> k = 1

The distance between the center of circle and the point through which the circle passes will be the radius.

The distance formula is given by:

r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Given

(x_1,y_1) = (-3,1)\\(x_2,y_2) = (-5,3)

Putting the values in the formula

r = \sqrt{(-5+3)^2+(3-1)^2}\\r = \sqrt{(-2)^2+(2)^2}\\r = \sqrt{4+4}\\r = \sqrt{8}

Putting the values of h,k and r in general form of equation

\{x-(-3)}^2\} +(y-1)^2 = (\sqrt{8})^2\\(x+3)^2+(y-1)^2 = 8

Hence,

Option B) (x + 3)^2 + (y – 1)^2 = 8 is the correct answer.

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Read 2 more answers
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