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rodikova [14]
3 years ago
11

What is the perimeter of the figure to the nearest tenth of a millimeter?

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
7 0
We have to calculate the perimeter of the figure to the nearest tenth of a millimeter. This figure is made of a rectangle and a half of a circle. The first figure has the perimeter: 3 + 6 + 3 = 12 mm. The second figure has the perimeter: 2 * Pi * r / 2 = Pi * r ; and the radius : r = 6/2 = 3 mm. So Pi * 3 = 3.14 * 3 = 9.42. Fimally : 12 + 9.42 = 21.42 or 21.4 to the nearest tenth. Answer: C. 21.4 millimeters<span>. </span>
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lawyer [7]
To find the dividend per share, we divide the total dividend amount by the total shares.
Dividend per share = 40,000 / 60,000
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Your share = 100 x 0.67
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3 0
3 years ago
What does it mean for a scatter plot to have a negative trend? A. Higher x-values tend to go with higher y-values. B. Higher x-v
BARSIC [14]

Answer:

Option D = None of these are related

Step-by-step explanation:

A scatter plot is said to have a negative trend if both x & y values are negative from the origin (0,0)

7 0
3 years ago
Three-fourths divided by 2 is?
Mariana [72]

Answer: i think 1/4

Step-by-step explanation: maybe i might be incorrect

3 0
3 years ago
Read 2 more answers
If a coin is flipped 75 times, in how many ways could there be exactly two tails?
Dimas [21]

Answer:

2775 ways

Step-by-step explanation:

We have been given the case to choose exactly two tails when flipped 75 times  means  ^{75}C_2

Since, ^nC_r is equal to \frac{n!}{r!\cdot(n-r)!}  

Here n =75, r=2 substituting the values we will get

\frac{75!}{2!(75-2)!}

n!=n\cdot (n-1)\cdot (n-2).....1

After simplification we will get  \frac{75\cdot 74\cdot 73!}{2!\cdot73!}

Cancel out the common term that is 73! we will get

after more simplification we will get \frac{75\cdot 74\cdot}{2!}

Finally, we will get \frac{75\cdot 74\cdot}{2}=75\cdot37=2775

4 0
3 years ago
Read 2 more answers
Find four consecutive integers such that the sum of the first and third is eight les than twice the sum of the second and fourth
lyudmila [28]
X, x+1, x+2, x+3 are 4 consecutive integers

2(x + x+2) = 5(x+3) - 26
2(2x+2) = 5(x+3) - 26
4x + 4 = 5x + 15 - 26
4x + 4 = 5x - 11
15 = x
15, 16, 17, 18

x, x+2, x+4 consecutive even integers
2(x+4)+11 = x + 9
2x + 8 + 11 = x + 9
2x + 19 = x + 9
x = -10
-10, -8, -6
5 0
3 years ago
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