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Ugo [173]
2 years ago
8

Where should string be attached to triangular-shaped pieces of cardboard so they will balance out the mobile

Mathematics
2 answers:
padilas [110]2 years ago
6 0
The answer is D. the centroid
Rus_ich [418]2 years ago
5 0

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we know that

Incenter - It is the centre of the incircle of the triangle and it is the point of intersection of the angle bisectors of the triangle.

Circumcenter - It is the point of intersection of perpendicular bisectors of the triangle. It is also the center of circumcircle.

Orthocenter - It is the point of intersection of the altitudes.

Centroid - It is the point of intersection of the medians.

String should be attached to triangular shaped pieces of cardboard, so they will balance out the mobile at the centroid because medians divide the triangle into equal parts.

Hence, Option 'D' is correct.

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What is log15 2^3 rewritten using the power property?
OlgaM077 [116]

ANSWER

log_{15}( {2}^{3} )  = 3 \: log_{15}( {2} )

EXPLANATION

According to the power property of logarithms:

log_{x}( {y}^{n} )  = n \: log_{x}( {y} )

The given logarithm is

log_{15}( {2}^{3} )

When we apply the power property to this logarithm, we get,

log_{15}( {2}^{3} )  = 3 \: log_{15}( {2} )

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3 years ago
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3.281 feet in word form
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Three and two eight one thousandths
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What equation is equivalent to 2(4x+3)-5x=1
matrenka [14]
8x+6-5x=1

3x+6=1

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3 years ago
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If U-235 has a half-life of 713 million years and the age of the sample is 2.631 billion years old then how many half-lifes has
lutik1710 [3]
<span>As the age of the U-235 sample is 2.631 billion years, and the half-life of U-235 is 713 million years, the sample has undergone 2.361 X 1,000,000,000 / 713 X 1,000,000 = 3.69 half lives. In each half-life the sample reduces to half its original weight according to the radioactive Half-Life Formula: ln (Nt /N0) = -kt, where N0 = mass of the original weight of radioactive material, Nt = mass of radioactive material at time t, k = decay constant and t = time interval . We have to put Nt/N0 = 1/2 for time interval = half-life.</span>
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As part of a study of the association between smoking and risk of squamous cell carcinoma, a logistic regression model was estim
AlekseyPX

Answer:

0.44

Step-by-step explanation:

Given the estimated logistic regression model on risk of having squamous cell carcinoma

-4.84 + 4.6*(SMOKER)

SMOKER = 0 (non-smoker) ; 1 (SMOKER)

What is the predicted probability of a smoker having squamous cell carcinoma?

exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))

SMOKER = 1

exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)

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0.7866278 / 1.7866278

= 0.4402863

= 0.44

3 0
2 years ago
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