Identify the equation that represents this solution & the correct solution.

Simplify. Evaluate the numerical bases. 3^2 b^2 c^-4 *3^-1 b^-5 c^7

photoshop1234 [79]

Hope I can be of assistance!

$3^2b^2c^{-4}\cdot \:3^{-1}b^{-5}c^7 \ \textgreater \ \mathrm{Apply\:exponent\:rule}:\ \:a^b\cdot \:a^c=a^{b+c}$
$3^{-1}\cdot \:3^2=\:3^{2-1}=\:3^1=\:3 \ \textgreater \ 3b^{-5}b^2c^{-4}c^7$

$\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \ b^{-5}b^2=\:b^{2-5}=\:b^{-3}$
$3b^{-3}c^{-4}c^7$

$\mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c} \ \textgreater \ c^{-4}c^7=\:c^{-4+7}=\:c^3$
$3b^{-3}c^3$

$\mathrm{Apply\:exponent\:rule}: \:a^{-b}=\frac{1}{a^b} \ \textgreater \ b^{-3}=\frac{1}{b^3} \ \textgreater \ 3\cdot \frac{1}{b^3}c^3$

$\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{1\cdot \:3c^3}{b^3}$

Finally
$\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \ \frac{3c^3}{b^3}$

Hope this helps!

8 0

4 years ago

Possible answers:<br> A) 336cm <br> B) 110m<br> C) 588m<br> D) 1,029m

kozerog [31]

Answer: The area of the enclosure is 1,029 square meters

Step-by-step explanation: The first thing is to use the unit of measurement required by the question, and to do this we need to convert what we have to what is required.

If the scale of the diagram is given as every 4cm represents 7m, that means, every unit of the actual measurement would be given as

(X/4) x 7

For the length of the enclosure, we can determine that as follows;

Length = (28/4) x 7

Length = 7 x 7

Length = 49m

And for the width,

Width = (12/4) x 7

Width = 3 x 7

Width = 21m

Therefore, the area is calculated as,

Area = L x W

Area = 49 x 21

Area = 1029 m²

5 0

3 years ago

Read 2 more answers

A loan of $900 will be repaid in 36 installment of $30.22 each .what is the finance charge for the loan

Marat540 [252]

i hope this is what you are looking for but 36 times 30.22 equals 1087.92 subtract from 900 which is $187.92

<h2>$187.92 for finance charge for loan</h2>

8 0

3 years ago

Pleaseeeeeeee helpppppppppppppp!!! :)

mrs_skeptik [129]

x=0.2

y=2.4

$\frac{0.2}{2.4} \\$

5 0

3 years ago

Read 2 more answers

Analyze this data, and match each percentage to the description it represents. Round your answers to the nearest whole number. 3

Aleksandr [31]

Answer:

(a)The percentage of hatchbacks that run on gasoline.=78%

(b) The percentage of diesel vehicles that are hatchbacks.=21%

(c)The percentage of SUVs that run on gasoline=30%

(d)The percentage of gasoline vehicles that are sedans=42%

(e)The percentage of sedans that run on diesel =44%

(f)The percentage of gasoline vehicles that SUVs.=8%

Step-by-step explanation:

This table gives information about vehicles sold at a dealership in a month.

------------------Gasoline-------Diesel

Hatchback------18---------------5

Sedan------------15---------------12

SUV----------------3----------------7

(a)The percentage of hatchbacks that run on gasoline.

Total Number of Hatchbacks=23

Number that run on Gasoline=18

Percentage that run on gasoline=(17/23)X100=78%

(b) The percentage of diesel vehicles that are hatchbacks.

Total Number of Diesel Vehicles=5+12+7=24

Number of Diesel Hatchbacks=5

Percentage of diesel vehicles that are hatchbacks=(5÷24)X100=21%

(c)The percentage of SUVs that run on gasoline

Total Number of SUVs=10

Number of Gasoline SUVs=3

Percentage of SUVs that run on gasoline=(3÷10)X100=30%

(d)The percentage of gasoline vehicles that are sedans.

Total Number of Gasoline Vehicles=18+15+3=36

Number of Gasoline sedans=15

Percentage of Sedans that run on gasoline=(15÷36)X100=42%

(e)The percentage of sedans that run on diesel

Total Number of Sedans=15+12=27

Number of Diesel Sedans=12

Percentage of sedan that run on diesel=(12÷27)X100=44%

(f)The percentage of gasoline vehicles that SUVs.

Total Number of Gasoline Vehicles=18+15+3=36

Number of Gasoline SUVs=3

Percentage of SUVs that run on gasoline=(3÷36)X100=8%

4 0

3 years ago