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timama [110]
3 years ago
15

How to answer this? TvT

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0
Since the midpoint lies on the axis, both ends are therefore equidistant from the axis and are mirrors of each other so..

Q = (4,9)
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25° decreased by 60%
worty [1.4K]
<span>25 - (60% × 25) =
</span><span>25 - 60% × 25 =
</span>(1 - 60%) × 25 =
<span>(100% - 60%) × 25 =
</span><span>40% × 25 =
</span><span>40 ÷ 100 × 25 =
</span><span>40 × 25 ÷ 100 =
</span><span>1,000 ÷ 100 =
</span><span>10;
The answer is 10</span>
4 0
3 years ago
About 16 % of the population of a large country is allergic to pollen. If two people are randomly selected, what is the probabil
Vinvika [58]

Answer:

(a) 0.0256

(b) 0.2944

Step-by-step explanation:

For solving this exercise we can apply the binomial distribution. The equation that give as the probability is:

P(x,n,p)=(nCx)*p^{x} *(1-p)^{n-x}

Where n is the number of identical events, p is the probability that the event has a success and x is the number of success in the n identical events.

Additionally, nCx is calculated as:

nCx=\frac{n!}{x!(n-x)!}

So, in this case we have 2 identical events because we are going to select two people randomly and the probability p of success is the probability that the person is allergic to pollen and this probability is 16%.

Then, for the first case, x is 2 because their are asking for the probability that both are allergic to pollen. Replacing the values of x, n and p we get:

P(2,2,0.16)=(2C2)*0.16^{2} *(1-0.16)^{2-2}

P(2,2,0.16)=0.0256

For the second case, their are asking for the probability that at least one is allergic to pollen, that means that we need to sum the probability that both are allergic to pollen with the probability that just one is allergic to pollen.

Using the same equation to calculate P(1,2,0.16) we get:

P(1,2,0.16)=(2C1)*0.16^{1} *(1-0.16)^{2-1}

P(1,2,0.16)=0.2688

So, the probability that at least one person is allergic to pollen is 0.2944 and it is calculated as:

0.0256 + 0.2688 = 0.2944

7 0
3 years ago
The value of which of these expressions is closest to e?
mars1129 [50]

Answer:

B.

Step-by-step explanation:

Given: expressions

To find: the expression whose value is closest to e

Solution:

Value of e is 2.718

\left ( 1+\frac{1}{19} \right )^{19}=\left ( \frac{20}{19} \right )^{19}=2.65\\\left ( 1+\frac{1}{22} \right )^{22}=\left ( \frac{23}{22} \right )^{22}=2.659\\\left ( 1+\frac{1}{20} \right )^{20}=\left ( \frac{21}{20} \right )^{20}=2.653\\\left ( 1+\frac{1}{21} \right )^{21}=\left ( \frac{22}{21} \right )^{21}=2.656

Therefore, value 2.659 is closest to the value of e.

So, option B. is correct.

7 0
3 years ago
The following question has two parts. First, answer part A. Then, answer part B.
Arturiano [62]

Answer:

  Part A:  13.2

  Part B:  see below

Step-by-step explanation:

<u>Part A</u>:

13.245 rounded to tenths is 13.2

<u>Part B</u>:

The rule is ...

  <em>Add 1 in the number place you're rounding to if the digit to its right is 5 or more. Drop (or zero) all digits to the right of the place you're rounding to.</em>

Here, the digit to the right of the tenths place is 4, so no action is taken other than dropping digits to the right of the tenths place.

3 0
3 years ago
6x3 + 8x2 – 2x + 4 and 10x3 + x2 + 11x + 9
balu736 [363]
6x3+8x2-2x+4=30-2x

10x3+x2+11x+9=21+13x
3 0
3 years ago
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