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Ivenika [448]
3 years ago
7

A 60-kilogram person stands on a compression spring. The spring constant is 2500 Newtons per meter What is the displacement of t

he spring?
A)0.00392M
B) 0.024m
C)0.1176m
D)0.2352M
Mathematics
1 answer:
Mademuasel [1]3 years ago
6 0
The answer is 0.024m

60-kilogram divided by 2500 Newtons per meter or 60/2500 is 0.024
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SOLUTION

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Then

\begin{gathered} 8x-24+4x=180 \\ 8x+4x-24=180 \\ 12x-24=180 \\ \text{Add 24 t o both sides } \\ 12x-24+24=180+24 \\ 12x=204 \\ \text{divide both sides by 12} \\ \frac{12x}{12}=\frac{204}{12} \\ \text{Then} \\ x=17 \end{gathered}

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x=17

Since

\begin{gathered} \angle NOP=(4x)^0 \\ \text{substitute the value of x, we have } \\ \angle NOP=4\times17=68^0 \\ \text{Hence } \\ \angle NOP=68^0 \end{gathered}

Therefore

The measure of angle NOP is 68⁰

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