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algol [13]
3 years ago
10

Suzy's Sculpting gym charges a $10 application fee and $12 per month for membership. Tami's Toning does not charge an applicatio

n fee, but charges $14 per month for membership. After how many months will the total cost of membership be the same for both gyms?
Mathematics
1 answer:
Andreas93 [3]3 years ago
6 0

Answer:

Total cost of membership will be the same for both gyms after 5 months.

Step-by-step explanation:

Given: Suzy's Sculpting gym charges a $10 application fee and $12 per month for membership.

Tami's Toning does not charge an application fee, but charges $14 per month for membership.

To find: After how many months will the total cost of membership be the same for both gyms

Solution:

Let t denotes number of months after which total cost of membership will be the same for both gyms

For Suzy's Sculpting gym,

Total charges = 10+12t

For Tami's Toning,

Total charges =14t

Now solve 10+12t=14t

10+12t=14t\\10=14t-12t\\10=2t\\t=\frac{10}{2}\\ t=5

So, total cost of membership will be the same for both gyms after 5 months.

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Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

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