the width (x) of the rectangle = 41 inches
Explanation:
let the width = x
twice the width = 2x
The length of a rectangle is 1 inch shorter than twice the width (x) = 2x - 1
length = 2x -1
Area of rectangle = length × breadth
area (y) = 3321 square inches
y = x × 2x - 1 = x(2x - 1)
3321 = 2x² - x
2x² - x - 3321 = 0
We use factorisation to find x:
a = 2, b = -1, c = -3321
a × c = 2(-3321) = -6642
The factors which gives -1 when we sum together but gives -6642 when we multiply together are -82 and +81
2x² -82x + 81x - 3321 = 0
2x(x - 41) + 81(x - 41) = 0
(2x + 81) (x - 41) = 0
(2x + 81) = 0 or (x - 41) = 0
2x + 81 = 0
2x = -81
x = -81/2 inches
(x - 41) = 0
x - 41 = 0
x = 41 inches
Since we can't have a negative number as the width, the width (x) of the rectangle = 41 inches
Answer:
what i need to do?
Step-by-step explanation:
Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:For the student to be considered for the tutoring or extension activities, his/her score must be 20 points lower or higher than the average.
The average is given as 105, that means:
Minimum score to be considered = 105 - 20 = 85
Maximum score to be considered = 105 + 20 = 125
If p represents the performance of a student, then this inequality will be represented as follows:
85 ≤ p ≤125
Answer:
Pipe 1 twice as fast as pipe 2.
(Pipe 1 time * Pipe 2 time) / (Pipe 1 time + Pipe 2 time) = combined time
(x * (x/2)) / (x + x/2) = 10
(x^2/2) / 1.5 x = 10
x^2 / 2 = 15 x
x^2 /2 - 15 x = 0
x = 30 (slow pipe)
x/2 = 15 (fast pipe)
So it would take 30 hours using the slow pipe only.
Step-by-step explanation: