To write the given quadratic equation to its vertex form, we first form a perfect square.
x² - 2x + 5 = 0
Transpose the constant to other side of the equation,
x² - 2x = -5
Complete the square in the left side of the equation,
x² - 2x + (-2/1(2))² = -5 + (-2/1(2))²
Performed the operation,
x² - 2x + 1 = -5 + 1
Factor the left side of the equation,
(x - 1)² = -4
Thus, the vertex form of the equation is,
<em> (x-1)² + 4 = 0</em>
I think it might be c or A
Answer:h=−5t2−10t+70
Step-by-step explanation:
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Answer:
the equality shown is : x is greater than or equal to -3.
Y= 1x because the slope is 1 because rise over run 1
