this formula, doesn't rely on a product, relies on a "sum", or is namely an arithmetic sequence, aₙ₋₁ -3 is another way of saying, the value of the previous term minus 3, so it relies on the ordinal value of a term, so is an recursive formula, well, let's get it when n = 4.
9514 1404 393
Answer:
8.6 km
Step-by-step explanation:
The circumference of a circle is given in terms of its radius as ...
C = 2πr
Then the radius can be found from the circumference using ...
r = C/(2π)
Filling in the given values, we find the radius to be ...
r = (54 km)/(2·2.14) = (54 km)/6.28 ≈ 8.59873 km
The radius is about 8.6 km.
Answer:
![67.5\text{ [square units]}](https://tex.z-dn.net/?f=67.5%5Ctext%7B%20%5Bsquare%20units%5D%7D)
Step-by-step explanation:
The composite figure consists of one rectangle and two triangles. We can add up the area of these individual shapes to find the total area of the irregular figure.
<u>Formulas</u>:
- Area of rectangle with base
and height 
: 
- Area of triangle with base and height :
By definition, the base and height must intersect at a 90 degree angle.
The rectangle has a base of 10 and a height of 5. Therefore, its area is 
.
The smaller triangle to the left of the rectangle has a base of 2 and a height of 5. Therefore, its area is 
.
Finally, the larger triangle on top of the rectangle has a base of 5 and a height of 5. Therefore, its area is 
.
Thus, the area of the total irregular figure is:
![50+5+12.5=\boxed{67.5\text{ [square units]}}](https://tex.z-dn.net/?f=50%2B5%2B12.5%3D%5Cboxed%7B67.5%5Ctext%7B%20%5Bsquare%20units%5D%7D%7D)
Answer:
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Step-by-step explanation:
Given
Volume of a box = length × breadth × height= l×b×h
In this case the box have a square base. i.e l=b
Volume V = l^2 × h
The surface area of a square box
S = 2(lb+lh+bh)
S = 2(l^2 + lh + lh) since l=b
S = 2(l^2 + 2lh)
Given that the box is open top.
S = l^2 + 4lh
And Surface Area of the box is 1200cm^2
1200 = l^2 + 4lh ....1
Making h the subject of formula
h = (1200 - l^2)/4l .....2
Volume is given as
V = l^2 × h
V = l^2 ×(1200 - l^2)/4l
V = (1200l - l^3)/4
the maximum point is at dV/dl = 0
dV/dl = (1200 - 3l^2)/4
dV/dl = (1200 - 3l^2)/4 = 0
3l^2= 1200
l^2 = 1200/3 = 400
l = √400
I = 20cm
Since,
h = (1200 - l^2)/4l
h = (1200 - 20^2)/4×20
h = (800)/80
h = 10cm
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Answer:
Step-by-step explanation:
you can draw a table that has 7 rows and 7 columns, put the 6 numbers and their difference( 1-1=0, 1-2= -1, 1-3= -2,...)
- 1 2 3 4 5 6
1 0 1 2 3 4 5
2 -1 0 1 2 3 4
3 -2 -1 0 1 2 3
4 -3 -2 -1 0 1 2
5 -4 -3 -2 -1 0 1
6 -5 -4 -3 -2 -1 0
