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Delicious77 [7]
4 years ago
7

A parking lot charges $1.50 for the first hour of of parking and 55 cents for each additional half hour.how much would it cost t

o park a car from 12:45p.m.to 6:15p.m?
Mathematics
2 answers:
klasskru [66]4 years ago
7 0
$5.90
because..... the first hour would be till 1:45 p.m. which would cost 1.50, so you put those numbers aside.
so now, you work with 1:45 p.m to 6:15 p.m.
just to make it look easier to look at, you can add the 15  extra minutes from 6:15, to 1:45,
so now, you work with whole times, 2 p.m and 6 p.m.
continuing, you find the difference between the two. 6-2= 4 hour difference.
In an hour(60minutes) there are 2 (30minutes). ---> 30mins.*2 = 60mins.
so you take the 4 hours, and multiply it by 2 to find the amount of 30 minutes there are in 4 hours.... 4*2= 8
Now, you multiply 0.55 (the cost for every extra 30 minutes) and 8 (the number of 30 extra minutes in the extra time) = 4.40
You then add 4.40 and 1.50 ( for the first hour) and get $5.90
Debora [2.8K]4 years ago
3 0
 I think the answer is $4.25
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mars1129 [50]

Answer:

Ana is correct

Step-by-step explanation:

Given

Sequence:\ -10, -4, 2,8

Carlos; f(n) = -10 + 6n

Ana; f(n) = -10 + 6(n-1)

Required

Determine who is right?

To do this, we simply test each sequence.

For Carlos:

When n = 1

f(1) = -10 + 6 * 1 = -10 + 6 = -4

When n = 2

f(2) = -10 + 6 * 2 = -10 + 12 = 2

<em>This is incorrect because the first and second term of the sequence are -10 and -4 not -4 and 2</em>

<em></em>

For Ana:

When n = 1

f(1) = -10 + 6(1-1) = -10 + 6*0 = -10 + 0 = -10

When n = 2

f(2) = -10 + 6(2-1) = -10 + 6*1 = -10 + 6 = -4

When n=3

f(3) = -10 + 6(3-1) = -10 + 6*2 = -10 + 12 = 2

When n = 4

f(4) = -10 + 6(4-1) = -10 + 6*3 = -10 + 18 = 8

This is correct.

<em>Hence, Ana is correct</em>

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Answer:

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Step-by-step explanation:

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Step 3: Replace variables

2(3)² + 3(11)

Step 4: Evaluate

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