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3 years ago

What graphsfunction f(x) = 4representsthe

Mathematics

2 answers:

kolbaska11 [484]3 years ago

4 0

Answer:

constant function

Step-by-step explanation:

blagie [28]3 years ago

3 0

X=2 that is the correct answer

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Nick and his cousin Sara have the same birthday, but Nick is four years older than Sara. Let the variable X relresent Nick's age

Ronch [10]

Answer:

Let X represent Nick's age and Y represent Sara's age.

Then, it is given that: Nick is four years older than Sara.

We write the statement as:

$X=4+Y$

or $Y=X-4$

The only ordered pairs (X,Y) which satisfy the equation are: (0,-4) and (4,0) as you can see in the graph also.

In the graph X axis represents the age of Nick's age and Y-axis represent the age of Sara's age and the line Y=X-4 represents the relationship between the age of both.

6 0

3 years ago

1 1/2 divided by $0.99?

saw5 [17]

11/2 divided by $0.99 is $<span>1.51</span>

8 0

3 years ago

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

3 years ago

PLEASE HELP ME ASAP!

AleksandrR [38]

Ok so first we find the equation that equals one variable.

2y = -x + 9

3x - 6y = -15

We solve for y.

2y = -x + 9

y = -x/2 + 9/2

Then we plug in this y value into the other equation to keep only one variable so we can solve for it.

3x - 6y = -15

3(-x + 9/2) - 6y = -15

-3x + 27/2 - 6y = -15

-9y + 27/2 = -15

-9y = 3/2

-y = 3/18

y = -3/18

Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.

y = -x/2 + 9/2

-3/18 = -x/2 + 9/2

-84/18 = -x/2

-x = 9 1/3

x = -28/3

Your answer would be (-28/3, -3/18)

Hope this helps!

6 0

3 years ago

Read 2 more answers

Each group of three digits separated by commas in a multi digit number

ratelena [41]

You didn't ask a question but its called a period

6 0

3 years ago

What graphsfunction f(x) = 4representsthe​

What graphsfunction f(x) = 4representsthe