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Paraphin [41]
3 years ago
5

What graphsfunction f(x) = 4representsthe​

Mathematics
2 answers:
kolbaska11 [484]3 years ago
4 0

Answer:

constant function

Step-by-step explanation:

blagie [28]3 years ago
3 0
X=2 that is the correct answer
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To move a graph up c units, add c to the whole function

so basicaly what you did is you subtraced 3 from the whole function

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B is answer
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Tony plans to run a 5,000-meter fun run at a constant rate of 250 meters per minute. He uses function f to model his distance fr
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Answer:

Option A.

Step-by-step explanation:

Based on the information provided on the question

the function used to model Tony's run is:

f(x) = -250*x  + 5000

This means that after x = 20 minutes, Tony will arrive to the finish line

f(20) = -250*(20)  + 5000 = -5000 + 5000 = 0

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Katena32 [7]

Answer:

(a)

5^{-3}=\frac{1}{125}

(b)

-5^{-3}=-\frac{1}{125}

(c)

(-5^{-3})^{-1}=-125

(d)

(-5^{-3})^{0}=1

Step-by-step explanation:

(a)

5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

5^{-3}=\frac{1}{5^3}

5^{-3}=\frac{1}{5\times 5\times 5}

5^{-3}=\frac{1}{125}........Answer

(b)

-5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

-5^{-3}=-\frac{1}{5^3}

-5^{-3}=-\frac{1}{5\times 5\times 5}

-5^{-3}=-\frac{1}{125}........Answer

(c)

(-5^{-3})^{-1}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{-1}=(-5)^{-3\times -1}

(-5^{-3})^{-1}=(-5)^3

(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)

(-5^{-3})^{-1}=-125........Answer

(d)

(-5^{-3})^{0}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{0}=(-5)^{-3\times 0}

(-5^{-3})^{-1}=(-5)^0

we can use property

a^0=1

(-5^{-3})^{0}=1........Answer

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3 years ago
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