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belka [17]
3 years ago
5

Side B C is 10 inches long, and Side A B is StartRoot 300 EndRoot inches long. What is the length of Side A C?

Mathematics
2 answers:
anastassius [24]3 years ago
7 0

Answer:

option b

Step-by-step explanation:

kodGreya [7K]3 years ago
5 0

Answer:

The correct answer is B. StartRoot 200 EndRoot in.

Step-by-step explanation:

I just did the assignment.

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Harry has half as many comics
vesna_86 [32]

Answer:

2

Step-by-step explanation:

Tomas- 1/4 =4

harry-4 =2

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3 years ago
Write the equation for a line perpendicular to y=-3x+18 that goes through the point (-12,6)
Hatshy [7]

Answer:

y=\frac{1}{3} x -14

Step-by-step explanation:

The equation of the line you will find should be in the form y =mx+c , where m is the gradient and c is the y intercept.

The gradient of a line that is perpendicular to a line [of a known gradient] is the negative reciprocal of the gradient of the first. i.e. if a is the known gradient and the perpendicular gradient is b, ab = -1. Therefore the -3b=-1 and b= 1/3

you can now write y = mx +c as y = 1/3x +c

As you have been given a coordinate, you can input these values into y= 1/3x + c

-12 = 1/3(6) +c

-12 - 2 = c

c = -14

hence the equation of the line is y= 1/3x -14

5 0
3 years ago
Solve x: 60 pts if u can figure it out and the first one gets brainiest answer
jenyasd209 [6]

Answer:

11.65

Step-by-step explanation:

3x+99x=102x

1188/102=11.65

6 0
2 years ago
Read 2 more answers
May someone help me out with this question please
mario62 [17]

You would have 60 different types of pens with this brand. You need to multiply 12 and 5 (because you have 12 different colors for every type of tip, so you have 5 groups of 12).

8 0
3 years ago
Simplify the expression
kow [346]

Answer:

<h3>           f(x) = 5x² + 2x</h3><h3>           g(x) = 6x - 6</h3>

Step-by-step explanation:

\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}\\\\6(x^2-3x+2)\ne0\ \iff\ x=\frac{3\pm\sqrt{9-8}}{2}\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\\\\\\\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}=\dfrac{x(5x^2-8x-4)}{6(x^2-3x+2)}=\dfrac{x(5x^2-10x+2x-4)}{6(x^2-2x-x+2)}=\\\\\\=\dfrac{x[5x(x-2)+2(x-2)]}{6[x(x-2)-(x-2)]} =\dfrac{x(x-2)(5x+2)}{6(x-2)(x-1)}=\dfrac{x(5x+2)}{6(x-1)}=\dfrac{5x^2+2x}{6x-6}\\\\\\f(x)=5x^2+2x\\\\g(x)=6x-6

4 0
3 years ago
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