To find the 'maximum height' we will need to take the derivative of h(t) = –16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.
The equation y - 8 = 1/3 ( x + 2) has a slope form for the line that has a slope 1/3 and passes through (-2,8). The answer to the question is y - 8 = 1/3 (x + 2).
