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3 years ago

A ball is thrown into the air with an upward

1 answer:

5 0

To find the 'maximum height' we will need to take the derivative of h(t) = –16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.

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A cylindrical plastic pipe’s length is 12 cm and it’s radius is 2.5 cm. To the nearest tenth, what is the volume of the pipe?

NemiM [27]

Answer:

V = 235.6 cm³

Step-by-step explanation:

the formula for the volume of a cylinder of radius r and length h is

V = πr²h.

Here, r = 2.5 cm and h = 12 cm, so the volume is:

V = π(2.5 cm)²(12 cm) = 75π cm³

To the nearest tenth, this volume would be V = 235.6 cm³

7 0

3 years ago

Read 2 more answers

Laquita practiced 60 math facts. Kinman practiced 15 more facts than Laquita. How many math facts did they practice in all?

Afina-wow [57]

Answer:

They practiced a total of 75 math facts in all!

60 + 15 = 75 :D

5 0

2 years ago

You need to buy tissue paper sheets to cushion gifts being placed inside a box. The box is 12 inches wide by 16 inches long. The

Kay [80]

Answer:

Area of tissue paper is 384 square inches.

Step-by-step explanation:

Given:

Length of box = 16 inches.

Width of the box = 12 inches.

We need to find find the area of the tissue paper.

But It is given that the area of the tissue paper sheet is based on twice the length times the width of the box.

Hence Framing in equation form we get;

Area of tissue paper = $2(length\ of \ box \times width \ of \ box)$

Hence Substituting the given values we get;

Area of tissue paper = $2(12\times 16) = 2\times 192 = 384 in^2$

Hence Area of tissue paper is 384 square inches.

7 0

2 years ago

|-16| + |-12| =

bagirrra123 [75]

The |...| means absolute value meaning everything inside is a positive number. The first problem is 16+12= 28. |-5|= 5

4 0

3 years ago

Solve the following inequality.

Luden [163]

First simplify.
$-\frac{2}{3}x \ \textgreater \ \mathrm{Multiply\:fractions}:\ \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ -\frac{2x}{3}$

$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)} \ \textgreater \ \ \textgreater \ \frac{2x}{3}\ \textless \ -8$

$\mathrm{Multiply\:both\:sides\:by\:}3 \ \textgreater \ \frac{3\cdot \:2x}{3}\ \textless \ 3\left(-8\right) \ \textgreater \ Simplify \ \textgreater \ 2x\ \textless \ -24$

$\mathrm{Divide\:both\:sides\:by\:}2 \ \textgreater \ \frac{2x}{2}\ \textless \ \frac{-24}{2} \ \textgreater \ Simplify \ \textgreater \ x\ \textless \ -12$

$Therefore\; x\ \textless \ -12 \;is\;our\;answer!$

Hope this helps!

7 0

2 years ago