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Sedbober [7]
3 years ago
8

Solve for rv = 4/3 r^3​

Mathematics
1 answer:
sergejj [24]3 years ago
8 0

Answer:

r=\sqrt[3]{\frac{3v}{4} }

Step-by-step explanation:

To solve for r:

v=\frac{4}{3}r^{3} (given)

\frac{3v}{4}=r^{3} (times \frac{3}{4} on both sides)

r=\sqrt[3]{\frac{3v}{4} }

I hope this helps :)

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1. The hypotenuse of a right triangle measures 2 sqrt 15 centimeters and its shorter leg measures 2 sqrt 6
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Answer:

<h2>50.8°</h2>

Step-by-step explanation:

First, we need to use the Pythagorean Theorem to find the third side. We will then use the law of cosines to find the angle.

2√15² = 2√6² + b²

60 = 24 + b²

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Now, that we have all three sides, we will use the law of cosines to figure out the angle.

c² = a² + b² - 2abCosC°

Substitute the values in.

6² = 2√15² + 2√6² - 2(2√15)(2√6)CosC°

36 = 60 + 24 - 2(37.947331922)CosC°

36 = 60 + 24 - 75.894663844CosC°

36 = 84 - 75.894663844CosC°

Subtract 84

-48 = -75.9CosC°

0.63241106719 = CosC°

Arccos (0.63241106719) = 50.77176844°

The largest acute angle is approximately 50.8°

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