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BigorU [14]
4 years ago
7

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 15 N acts on

a certain object, the acceleration of the object is 5 /ms2. If the acceleration of the object becomes 9 /ms2, what is the force?
Mathematics
1 answer:
netineya [11]4 years ago
5 0

Answer:

27 N

Step-by-step explanation:

Since force varies directly with acceleration, we can introduce a constant, k, and write  F=ka

When force is 15, acceleration is 5, so plug it into the equation and solve for k:

F=ka\\15=k(5)\\k=\frac{15}{5}\\k=3

Now, to find force, we use a = 9 and k = 3, so

F=ka\\F=(3)(9)\\F=27

The force is 27 N

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Step-by-step explanation:

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For a normal distribution with μ=500 and σ=100, what is the minimum score necessary to be in the top 60% of the distribution?
STatiana [176]

Answer:

475.

Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

We will use z-score formula and normal distribution table to solve our given problem.

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Let us find z-score corresponding to normal score to 40% or 0.40.

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