Answer:
- c = -4.5
- z = 20
- x = -12
- a = -4/7
Step-by-step explanation:
A way to do this that will always work is ...
- eliminate parenthses and collect terms
- subtract any constants from the left side
- subtract any variable terms from the right side
- divide by the coefficient of the variable
1.
- 8c -11 -6c = -2
- 2c -11 = -2
- 2c = 9
- c = 4.5
2.
- 3z +4 -2z -9 = 15
- z -5 = 15
- z = 20
3.
- 12 -4x +18 = 36 +4x +18 -6x
- 30 -4x = 54 -2x
- -4x = 24 -2x
- -2x = 24
- x = -12
4.
- 36a -9a -5 = 6a -17
- 27a -5 = 6a -17
- 27a = 6a -12
- 21a = -12
- a = -12/21 = -4/7
HOPE THIIIISSS HELLLPSSSS
Answer:
The angle it turns through if it sweeps an area of 48 cm² is 448.8°
Step-by-step explanation:
If the length of a minute hand of a clock is 3.5cm, to find the angle it turns through if it sweeps an area of 48 cm, we will follow the steps below;
area of a sector = Ф/360 × πr²
where Ф is the angle, r is the radius π is a constant
from the question given, the length of the minute hand is 3.5 cm, this implies that radius r = 3.5
Ф =? area of the sector= 48 cm² π = 
we can now go ahead to substitute the values into the formula and solve Ф
area of a sector = Ф/360 × πr²
48 = Ф/360 ×
× (3.5)²
48 = Ф/360 ×
×12.25
48 = 269.5Ф / 2520
multiply both-side of the equation by 2520
48×2520 = 269.5Ф
120960 = 269.5Ф
divide both-side of the equation by 269.5
448.8≈Ф
Ф = 448.8°
The angle it turns through if it sweeps an area of 48 cm² is 448.8°