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3 years ago

Graph the equations to solve the system. y=-1/2x y=-1/3x+1

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

3 0

Answer:

The solution to the system of equations is (-6, 3)

Step-by-step explanation:

Plot both lines on a graph, find where they intersect IF they even intersect at all like in this case, and boom there's your answer. Hope that helps and have a good rest of your day.

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Can anyone explain how you graph things for example, like y=x-4 how would you graph that

Savatey [412]

Answer:

In basicallity if a question such as this pops up, the correct way to go would first be to graph this. y=x-4 would be equivalent to x=4.

My paper work is below:

y = x - 4

0 = x - 4

-x = -4

x = 4

Hope this helped..

8 0

3 years ago

I need help. Whats 50(3)^20?

Alex

Answer:

174339220050

Step-by-step explanation:

50(3^20)

=(50)(3486784401)

=174339220050

8 0

3 years ago

Read 2 more answers

Calvin's rug covers 1/8 of the floor space in his bedroom how much floor space would be covered if Calvin had four rugs of that

djverab [1.8K]

Answer:

I dont really know what this is asking but i think it would be 4/8 or 1/2

Step-by-step explanation:

Im sorry if its wrong

7 0

3 years ago

In football, a kicker can score one point for the extra-point on a touchdown or three points for a field goal.

White raven [17]

I am not sure but i will try to help

In football, a kicker can score one point for the extra point on a touchdown or three points for a field goal. logan is a kicker for his high school football team. the record number of points scored by a kicker in a single game is 24

3 0

3 years ago

This is a question on my partial fractions homework, but no matter what I try I can't figure it out..

Ierofanga [76]

$\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}$
$\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}$
$\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)$
$\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3$

So you have

$\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$
$=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}$

where in the first integral we substitute $x\mapsto x+1$ .

$=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}$
$=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)$
$=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2$
$=\dfrac23+\ln\dfrac89$

4 0

3 years ago