The function h(x) is a transformation of the square root parent function,
f(x)=√x. The function is h(x) A: √x+5.
<h3>What is Transformations?</h3>
Transformations come in the form;
y =√(x-h) +k,
where h is responsible for left-right movements, and k is responsible for up-down movements.
From the graph, we can see that f(x) is simply the parent square root function, √x.
To translate a function right by p units and up by q units, the function becomes
g(x) = f(x -p) +q
(p, q) = (5, 0)
To get h(x), there is a translation of 5 units to the left, which can be represented by a value of h = -5.
h(x) = f(x + 5) +0
h(x) = √(x+ 5)
Hence, The function h(x) is a transformation of the square root parent function, f(x)=√x. The function is h(x) A: √x+5.
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Hey! So you’re gonna need to use the Pythagorean Theorem (a^2 + b^2 = c^2).
You’re looking for one of the legs here, so after inputting the values your equations should look like this: 6^2 + b^2 = 10^2.
Next, find what the numbers squared are: 36 + b^2 = 100.
Then, isolate the variable: b^2 = 64.
Lastly, square root both sides: √b^2 = √64.
You should find the answer is 8.
Answer:
Well, "b" is just a variable. It's not really the function. I'm not quite sure what your asking. It can't be 1 because it can't. Math was founded on these mathematical laws. Consider talking to your teacher about this for further explanation.
Step-by-step explanation:
Answer:
158
Step-by-step explanation:
4 x 5 is 20. 73 - 20 is 53. 53 x 2 is 106, and when you add 52, you get 158
Answer: 60
Step-by-step explanation:
Given : The number of choices for different temperatures = 3
The number of choices for different pressures = 4
The number of choices for different catalyst = 5
Since , the experimenter is studying the effects of temperature, pressure, and different type of catalysts.
Then by using the Fundamental principle of counting , we have
The number of experimental runs are available = (number of choices for temperatures ) x (number of choices for pressures) x( number of choices for catalyst)
= 3 x 4 x 5 = 60
Hence, the number of experimental runs are available = 60
