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creativ13 [48]
3 years ago
6

What is 12 1/2% of 168

Mathematics
1 answer:
egoroff_w [7]3 years ago
4 0
The answer to the question is 21
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I need help on 4 and 6 please help me. Don’t put a link.
Arte-miy333 [17]

Answer:

I don't know about 4 but of no. 6, it is A

Step-by-step explanation:

3 0
2 years ago
Answer both please, the topic is linear inequalities, and please explain it to me.
Bogdan [553]
<u>Question 1 solution:</u>
You have two unknowns here:

Let the Water current speed = W

Let Rita's average speed = R

We are given <em>two </em>situations, where we can form <em>two equations</em>, and therefore solve for the <em>two unknowns, W, R</em>:

Part 1)  W→ , R←(against current, upstream) 
If Rita is paddling at 2mi/hr against the current, this means that the current is trying to slow her down. If you look at the direction of the water, it is "opposing" Rita, it is "opposite", therefore, our equation must have a negative sign for water<span>:  

</span>R–W=2  - equation 1

Part 2)  W→ , R<span>→</span>(with current)
Therefore, R+W=3  - equation 2

From equation 1, W=R-2, 
Substitute into equation 2.
R+(R–2)=3
2R=5
R=5/2mi/hr

So when W=0 (still), R=5/2mi/hr

Finding the water speed using the same rearranging and substituting process:

1...               R=2+W
2...  (2+W)+W=3
                 2W=1
                   W=1/2mi/hr
 
7 0
3 years ago
Are the graphs of −5y=2x+3 and y=25x+4 parallel, perpendicular, or neither?
saw5 [17]
Parallel graphs have the same slope. perpendicular has opposite reciprocal slopes. These equations have slopes of -2/5 and 25 so they are neither.
6 0
3 years ago
Find mystery number
In-s [12.5K]

The number is less than 190,000 and greater than 180,000

5,000 more than the number has 187 thousands

2000 less than the number has 4 hundreds


180, 000 <n> 190, 000

180,000 + 2000 = n = 5000-187, 000

182,000 = n = 182, 000  

Or,  

 180, 000 <n> 190,000                    

 n + 5000= 187, 000                           n – 2000 = 180, 000

 n= 187, 000- 5000                             n = 180, 000 + 2000

 n= 182, 000                                       n= 182, 000

5 0
3 years ago
There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl
insens350 [35]

We're told that

P(A\cap B)=0.15

P(A\cup B)^C=0.06\implies P(A\cup B)=0.94

P(B\mid A)=P(B^C\mid A)=0.5

where the last fact is due to the law of total probability:

P(A)=P(A\cap B)+P(A\cap B^C)

\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)

\implies 1=P(B\mid A)+P(B^C\mid A)

so that B\mid A and B^C\mid A are complementary.

By definition of conditional probability, we have

P(B\mid A)=P(B^C\mid A)

\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}

\implies P(A\cap B)=P(A\cap B^C)

We make use of the addition rule and complementary probabilities to rewrite this as

P(A\cap B)=P(A\cap B^C)

\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)

\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)

\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]

\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]

\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C

\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)

By the law of total probability,

P(B)=P(A\cap B)+P(A^C\cap B)

\implies P(A^C\cap B)=P(B)-P(A\cap B)

and substituting this into (*) gives

2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]

\implies P(B)=P(A\cup B)-P(A\cap B)

\implies P(B)=0.94-0.15=\boxed{0.79}

8 0
3 years ago
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