If RS is the hypotenuse of the triangle RST and point T is in Quadrant 3, then point T must be the intersection of the lines: x = - 4 and y = - 5.
Therefore, the coordinates of point T are ( x, y ) = ( - 4, - 5 )
Answer:
T ( - 4, - 5 )
(4-6i)(6-8i)
24-32i-36i+48i²
24 + -68i - 48
-24-68i
525/538=0.975 (round up Bc of the 5)
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