All categories

2 years ago

1 and 5/8 or 1 and 16/25 which is bigger

Mathematics

1 answer:

BARSIC [14]2 years ago

6 0

1 and 16/25 is bigger than 1 and 5/8

You might be interested in

How to start the problem off. (substitution)

otez555 [7]

Do you have to use substitution?

5 0

3 years ago

Mr. Gurney purchased 3 dozen

DedPeter [7]

If mr Gurney purchased 5 dozen eggs it would be 9.55

8 0

3 years ago

(x + 2) is raised to the fifth power. The third term of the expansion is:

morpeh [17]

Answer:

Step-by-step explanation:

6 0

2 years ago

Begin by clearly stating the problem; you can copy this from the problem set file. Show how you solved the problem step by step,

Y_Kistochka [10]

Answer: 13%

Step-by-step explanation:

The formula to find the simple interest is given by :-

$I=Prt$ , where P is the principal amount, r is rate of interest () in decimal and t is the time ( in years).

Given : P = $19,100 , I=$9932.00 and t= 4 years

Substitute all the above values in the formula , we get

$9932.00=(19100)r(4)\\\\\Rightarrow\ r=\dfrac{9932}{19100\times4}\\\\\Rightarrow r=\dfrac{13}{100}=0.13$

In percent , $r=0.13\times100=13\%$

Hence, the rate of interest = 13%

6 0

3 years ago

Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear

AlladinOne [14]

Answer:

$x=\frac{83}{50}$

Step-by-step explanation:

we know that

If the three points are collinear

then

$m_A_B=m_A_C$

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope AB

we have

$A(1,\frac{2}{3}),B(x,-\frac{4}{5})$

substitute in the formula

$m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}$

$m_A_B=\frac{\frac{-12-10}{15}}{x-1}$

$m_A_B=-\frac{22}{15(x-1)}$

step 2

Find the slope AC

we have

$A(1,\frac{2}{3}),C(-\frac{1}{2},4)$

substitute in the formula

$m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}$

$m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}$

$m_A_C=-\frac{20}{9}$

step 3

Equate the slopes

$m_A_B=m_A_C$

$-\frac{22}{15(x-1)}=-\frac{20}{9}$

solve for x

$15(x-1)20=22(9)$

$300x-300=198$

$300x=198+300$

$300x=498$

$x=\frac{498}{300}$

simplify

$x=\frac{83}{50}$

8 0

3 years ago