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The diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 mi

Assoli18 [71]

Answer:

Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

Step-by-step explanation:

We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.

Firstly, Let X = diameters of ball bearings

The z score probability distribution for is given by;

Z = $\frac{ X - \mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean diameter = 106 millimeters

$\sigma$ = standard deviation = 4 millimeter

Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)

P(X > 111) = P( $\frac{ X - \mu}{\sigma}$ > $\frac{111-106}{4}$ ) = P(Z > 1.25) = 1 - P(Z $\leq$ 1.25)

= 1 - 0.89435 = 0.1056

Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

4 0

2 years ago

Write a compound inequality that the graph could represent.

Dmitry_Shevchenko [17]

A solid dot on the graph of an inequality indicates that the number is contained within the inequality, so yo should use $\leq$ or $\geq$ to represent that situation, whereas a white dot indicates that the number is not contained within the inequality.

Our graph is telling us that $x$ is greater or equal than -1, and also $x$ is less than 3. So our inequality will be:

$-1 \leq x \leq 3$

3 0

3 years ago

Read 2 more answers

The graph of the function f(x) = –(x + 6)(x + 2) is shown below.

schepotkina [342]

Answer:

a. The function is increasing for all real values of x where x < –4.

Step-by-step explanation:

Let me help you, I have answered this question once in Brainly as well

Given the factored form of the function:

f(x) = -(x + 6)(x+2)

<=> f(x) = $-x^{2} - 8x -12$