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skad [1K]
3 years ago
15

The area of a playground is 204 yards squared the width of a playground at 5 yards longer than its length whats the length and t

he width of the playground
Mathematics
1 answer:
Ilya [14]3 years ago
6 0
W= width= L+5
L= length
Area= 204

Area= LW
204 square yards= LW
substitute w=L+5 for w
204= (L)(L+5)
204= L^2 + 5L
subtract 204 from both sides
0= L^2 + 5L - 204
factor
0= (L+17)(L-12)

0= L+17
-17= L

0= L-12
12 yards= L


WIDTH
Since the area cannot be a negative number, we'll use L=12 to find the width.

w=L+5
w=12+5
w=17 yards


CHECK:
204=(12)(17)
204=204


ANSWER: The length is 12 yards and the width is 17 yards.

Hope this helps! :)
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Please help thank you.
Mnenie [13.5K]

Answer:

Option D

Step-by-step explanation:

Whenever we take a square root of a number the ± sign is with it like here in the question

x^2=20\\\\Apply\ square\ root\ on\ both\ sides\\sqrt{x^2}=\sqrt{20}  \\\\The\ square\ cancels\ out\ with\ the\ root\x=\sqrt{20}

And then x = ±4.47 which means x has two values one is +4.47 and the other is -4.47 so Option D is our answer.

7 0
2 years ago
The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.
zzz [600]
Hello,

u_{1} =-5\\
 u_{2} =-5+d\\
 u_{3} =-5+2d\\
 u_{4} =-5+3d\\
...\\
 u_{10} =-5+9d=13\\
==\ \textgreater \  9d=18 \\
==\ \textgreater \  d=2


6 0
3 years ago
The average cost for a gallon of gasoline increased from $2.56 one year to $3.18 the next year. What is the percent of increase,
Kitty [74]
From 2.56 to 3.18; 3.18-2.56=0.62 increased 
so if 2.56 represented 100%
       0.62 represents     ? %
cross multiply 
?%= 0.62·100/2.56=24.21875 which rounded to the nearest whole is 24%
Answer is B).
7 0
3 years ago
Read 2 more answers
A statue that is 80 m tall stands on a 625 m2 base. An artist creates a replica using a ratio of 1:15. What is the area of the r
Sholpan [36]

Answer: 2.78m^{2}

Step-by-step explanation:

given data:

height of the statue = 80m.

base of the statue = 625m^{2}.

scale of the statue replica = 1:15.

<u><em>solution:</em></u>

= 1:15^{2} \\\\\= 1:225\\\\

= \frac{625m^{2} }{225}

= 2.78m^{2}

the area of the replica is 2.78m^{2}

4 0
2 years ago
M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,
timama [110]

Answer:

Step-by-step explanation:

Given

<LON = 77°

<LOM = (9x+44)°

<MON = (6x+3)°

The addition postulate is true for the given angles since tey have a common point O:

<LON = <LOM+<MON

Since we are not told what to find we can as well look for the value of x, <LOM and <MON

Substitute the given parameters and get x

77 = 9x+44+6x+3

77 = 15x+47

77-47 = 15x

30 = 15x

x = 30/15

x = 2

Get <LOM:

<LOM = 9x+44

<LOM = 9(2)+44

<LOM = 18+44

<LOM = 62°

Get <MON:

<MON = 6x+3

<MON = 6(2)+3

<MON = 12+3

<MON = 15°

6 0
3 years ago
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