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PIT_PIT [208]
3 years ago
5

find all integers x satisfying each of the following congruences mod n. if no such x exists, explain why not

Mathematics
1 answer:
zalisa [80]3 years ago
4 0

Answer:

please find the solution:

Step-by-step explanation:

please find the correct question:

Given value:  

\to 4x \equiv  2(mod\ n) \ \ \ \ \ \ \ \ \ \ \ \ _{where} \ \  n=6\\\\\to  4x \equiv  2 (mod 6)

\to 4x-2 should be divisible by 6  we are also given that 0 \leq x < n  and start with x = 0  

\to 4x-2 =-2 which is not divisible by 6  

x= 1  

\to 4x-2 = 2 not divisilble by 6  

x= 2

\to 4x-2 = 6 which is divisible by 6  

x=3  

\to 4x-2 = 10 not divisible by 6

x=4  

\to 4x-2  = 14 not divisible by 6  

x=5

\to 4x-2  = 18 which is divisible by 6  

so such x are x = 2 and x = 5

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What is the simplified form of the expression√1/196
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I'm assuming the square root is over the entire fraction (and not just over the 1). If so, then the answer is 1/14

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