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PIT_PIT [208]
3 years ago
5

find all integers x satisfying each of the following congruences mod n. if no such x exists, explain why not

Mathematics
1 answer:
zalisa [80]3 years ago
4 0

Answer:

please find the solution:

Step-by-step explanation:

please find the correct question:

Given value:  

\to 4x \equiv  2(mod\ n) \ \ \ \ \ \ \ \ \ \ \ \ _{where} \ \  n=6\\\\\to  4x \equiv  2 (mod 6)

\to 4x-2 should be divisible by 6  we are also given that 0 \leq x < n  and start with x = 0  

\to 4x-2 =-2 which is not divisible by 6  

x= 1  

\to 4x-2 = 2 not divisilble by 6  

x= 2

\to 4x-2 = 6 which is divisible by 6  

x=3  

\to 4x-2 = 10 not divisible by 6

x=4  

\to 4x-2  = 14 not divisible by 6  

x=5

\to 4x-2  = 18 which is divisible by 6  

so such x are x = 2 and x = 5

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I need help with Q9 c, I’ve done a and b if it helps, b=325 but I am just stuck on question 9C, I know the answer is 500N (as it
777dan777 [17]

Step-by-step explanation:

I know you've already done parts a and b, but I'll show the work for that before I do c.

Draw two free body diagrams, one for the car and one for the trailer.  The car pulls the trailer forward with a tension force T, so the trailer pulls backward on the car with an equal and opposite force T.

The car also has a 1200 N forward force from the engine, and a 200 N backwards force from resistance.

The trailer has a backwards resistance force of 100 N.

Sum of forces on the car:

∑F = ma

1200 − 200 − T = 900a

1000 − T = 900a

Sum of forces on the trailer:

∑F = ma

T − 100 = 300a

To solve the system of equations, first add the equations together.

1000 − 100 = 1200a

900 = 1200a

a = 0.75 m/s²

Plug back into either equation to find the tension force:

T = 325 N

Now for part c, draw new free body diagrams for the car and trailer.  This time, the car is pushing back on the trailer to slow it down.  So the trailer is pushing forward on the car with an equal and opposite force.  The magnitude of that tension force is given to be 100 N.

The car also has a backwards 200 N force from resistance, and a backwards brake force F.

The trailer has a backwards 100 N force from resistance.

Sum of forces on the car:

∑F = ma

100 − 200 − F = 900a

-100 − F = 900a

Sum of forces on the trailer:

∑F = ma

-100 − 100 = 300a

-200 = 300a

a = -⅔

Plugging into the first equation:

-100 − F = 900 (-⅔)

-100 − F = -600

F = 500 N

4 0
3 years ago
Mohammad would like to graph the line that represents the total number of baseball cards he will have collected, T, after m mont
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3 years ago
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PLEASE HELP!!!
Ksju [112]
ANSWER

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EXPLANATION

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ax = 6

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\Rightarrow \: \frac{ax}{a} = \frac{6}{a}

Cancel out common factors on the left hand side,

\Rightarrow \: x = \frac{6}{a}

For this solution to be a whole number, thena should be a factor of
6.

The reason is that, factors of 6 will divide exactly in to 6 without a remainder, making the answer a whole number.

The whole numbers that are factors of 6 are,

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Note that, the set of whole numbers are,

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The domain of g(x) = 4x –12 is {2, 3, 6, 8}. What is the range
vlada-n [284]

Answer:

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Step-by-step explanation:

Given that,

The function is :

g(x) = 4x –12

The domain of the function is {2, 3, 6, 8}.

g(2) = 4(2) –12 = -4

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Answer:

b 2,557.51

Step-by-step explanation:

7 0
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