The surface area of cylinder is 8.625
, if the cylinder has 5 centimeters high and 1.5 cm of diameter.
Step-by-step explanation:
The given is,
Cylinder has a 5 centimeters height
Diameter of the cylinder is 1.5 centimeters
Step:1
Formula for the surface area of cylinder is,
......................................(1)
Where,
h - Height of cylinder
r - Radius of cylinder
From the values of h and r,
= 
r = 0.75 cm
From the formula,
= ( 2 × × 0.75 × 5 ) + ( 2 × × 
)
= ( 7.5 ) + ( 1.125 )
A = 8.625
Result:
The surface area of cylinder is 8.625 , if the cylinder has 5 centimeters high and 1.5 cm of diameter.
Answer:
C = 28.048
Step-by-step explanation:
Circumference = 2pi(r)
Area = pi(r)^2
62.6 = pi(r)^2
r^2 = 62.6/pi
r^2 = 19.926
r = 4.464
Therefore, circumference = 2pi(4.464)
= 28.048
Answer:
Solution: (-1, -1)
Step-by-step explanation:
y=4x+2
y=-4/3x-2
Solve by graphing.
First, you need to plot the y-intercept.
y=4x+<u>2</u>
2 will be your y-intercept.
Next, you plot your slope.
y=<u>4x</u>+2
From your y-intercept, you will go up 4 and right one space, if you run out of space go down 4 and left 1.
Now repeat the same steps for the next one.
y=-4/3x<u>-2</u>
Plot your y-intercept.
y=<u>-4/3x</u>-2
because your slope is negative you will go down 4 and right 3, if you run out of room go up 4 and left 3.
Then draw connecting lines and wherever the lines intersect, that's going to be your solution. In this case, the solution is (-1, -1).
Hope this helps :)
Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
