Answer:
uh uh uh uh uh I'll try uh uh uh uh uh
Answer:
Amount of gas that can be hold by Joe's tank = 16 gallons.
Step-by-step explanation:
Given that Joe's gas tank is 1/4 full. After he buys 6 gallons of gas, it is 5/8 full. Now we need to find about how many gallons can Joe's tank hold.
So let's find change that happened after filling the gas.
Change = (5/8 full) - (1/4 full)
Change = (5/8 - 1/4) full
Change = (5/8 - 2/8) full
Change = (5 - 2)/8 full
Change = 3/8 full
So that means 3/8 full happens in 6 gallons
then 1 full will happen in 6/(3/8) gallons = 6*(8/3) gallons = 48/3 gallons = 16 gallons
So the amount of gas that can be hold by Joe's tank = 16 gallons.
For question number ten, the first polynomial is equivalent to 8x^8, the second is 6x^8, the third is 8x^8, and the fourth is 8x^8. So, you should circle the second second term.
For question number 11, the first term is 3^12, the second term is 3^20, the third term is 3^12, and the fourth term is 3^12. So you should circle the second term.
For question number 12, the first term is 49, the second term is 49, and the third term is -49, and the fourth term is -49. So, you should circle the first two or last two.
