Grandpa gump is 63yrs old. His age is 2 years less than 5 times the age of billy Gump. How old is Billy?

What is the fully factored form of the expression 45x²y2 + 18x3

Llana [10]

Answer:

9x^2(5y^2 + 2x).

Step-by-step explanation:

First find the Greatest Common Factor of the 2 terms.

GCF of 18 and 45 = 9

GCF of x^2 and x^3 = x^2.

The complete GCF is therefore 9x^2.

So, dividing each term by the GCF, we obtain:

9x^2(5y^2 + 2x).

4 0

2 years ago

A conclusion drawn based on evidence from the story is:

Andre45 [30]

Answer:

textual evidence

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

3(6+4y) hurry uppp pleaseeeee

Ahat [919]

Answer:

=12y+18

Step-by-step explanation:

=(3)(6+4y)

=(3)(6)+(3)(4y)

=18+12y

=12y+18

4 0

3 years ago

A Game of Thrones fan predicts there is a 70% chance that her favorite character will survive the next season and a 75% chance t

zepelin [54]

Answer:

The probability that the second favorite character will die given that the first favorite character dies is 0.53

This kind of probability is called conditional probability

Explanation:

Name the events and their probabiities:

Event A: her favorite character will survive, so P (A) = 0.70

Event B: her her second favorite character will die, so P(B) = 0.75

Both characters will die ⇒ P (B and not A) = 0.16

You want to find P (B | not A).

That is the probability of the succes B (the second favorite character will die) given other event (not A or the first favorite character dies) is certain (it happens) and that is called conditional probability.

P (not A) is the complement probability of A, so P (not A) = 1 - P(A) = 1 - 0.7 = 0.3

So, you have P(B), P(not A) and want to find P (B | not A)

The definition of conditional probability is:

P (X | Y) = P (X and Y) / P (Y)

So, replacing with our terms, we get:

P ( B | not A) = P (B and not A) / P (not A) = 0.16 / 0.3 ≈ 0.53

5 0

3 years ago

Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

4 0

3 years ago