If DE=4x+10, EF= 2x-1, and DF=9x-15, Find DF
1 answer:
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Answer:
No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer
Step-by-step explanation:
From the graph of the circle
∵ The center of the circle F is at the origin
∴ F is (0 , 0)
∵ The circle passes through point (7 , 0)
- The length of the radius of the circle is the distance between
the center of the circle and a point on the circle
∴ r is the distance between points (0 , 0) and (7 , 0)
∴
∴ The length of the radius of the circle is 7 units
Let us find the distance between point (7 , -7) and the origin (0 , 0)
- If the distance is equal to the radius of the circle, then the point is on the circle
- If the distance is greater than the radius, then the point is outside the circle
- If the distance is less than the radius, then the point is inside the circle
∵ The distance =
∵ r = 7
∵ > 7
∴ The distance is greater than the radius of the circle
∴ Point (7 , -7) lies outside the circle
The correct answer is:
No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle
<em>Your answer is not correct, the correct answer is the 3rd answer</em>
Answer:
6Y
Step-by-step explanation:
We need to solve the statement ' Thrice the product of two and "Y" '.
Thrice means 3 times and product means multiply. It means we have to multiply 3,2 and Y.
Let the result is R. It can be calculated as follows :
We know that, 3×2 = 6
So,
Hence, Thrice the product of two and "Y" is 6Y.