For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
1x-2y
Step-by-step explanation:
You have to go down 2 on the y-axis and over to the right 1 on the x axis
No cause if I helmet cost $42 , 7 helmets will be $294.
$42 = 1 helmet
$? = 7 helmets
cross multiply = 42 × 7 = $294
Answer:71.4
Step-by-step explanation:140*51%
Answer:
2.8
x+8.7
Step-by-step explanation:
