Answer:
Explanation:
1)<u><em> Ionization equilibrium equation: given</em></u>
- H₂O(l) + H₂O(l) ⇌ H₃O⁺(aq) + OH⁻(aq)
2) <em><u>Ionization equilibrium constant, at 25°C, Kw: given</u></em>
<u>3) Stoichiometric mole ratio:</u>
As from the ionization equilibrium equation, as from the fact it is stated, the concentration of both ions, at 25°C, are equal:
- [H₃O⁺(aq)] = [OH⁻(aq)] = 1.0 × 10⁻⁷ M
- ⇒ Kw = [H3O⁺] [OH⁻] = 1.0 × 10⁻⁷ × 1.0 × 10⁻⁷ = 1.0 × 10⁻¹⁴ M
<u><em>4) A solution has a [OH⁻] = 3.4 × 10⁻⁵ M at 25 °C </em></u><em><u>and you need to calculate what the [H₃O⁺(aq)] is.</u></em>
Since the temperature is 25°, yet the value of Kw is the same, andy you can use these conditions:
Then you can substitute the known values and solve for the unknown:
- 1.0 × 10⁻¹⁴ M² = [H₃O⁺] × 3.4 × 10⁻⁵ M
- ⇒ [H₃O⁺] = 1.0 × 10⁻¹⁴ M² / ( 3.4 × 10⁻⁵ M ) = 2.9⁻¹⁰ M
As you see, the increase in the molar concentration of the ion [OH⁻] has caused the decrease in the molar concentration of the ion [H₃O⁺], to keep the equilibrium law valid.
Answer:
Refer to attached file below
Hope it helps..
Have a great day :P
Ok so next time maybe add that it explains the number of covalent bonds in the atom because... (and then explain CaF2 tendencies in following the octet rule, like if it adds to 8 or isn’t completed yet.)
If this isn’t enough I would highly recommend asking your teacher after class even if they don’t like you or are one of THOSE teachers they gotta help you or it’s not fair for them to count you off points.
The answer is A , an enzyme.
An enzyme is defined as a molecule which is protein in nature, that helps other organic molecules enter into chemical reactions with one another but is itself not affected by these reactions. It remains the same as it was before and after the reaction. In other words it acts as a catalyst for organic biochemical reactions.
Enzymes are usually very selective in the molecules that they act upon, called substrates, often reacting only with a single substrate.
Enzymes can quicken reactions by a thousand fold but will only be able to work within a narrow range of temperature and pH, outside of which they can lose their structure and become denatured.