Answer:
in 6.0 E3 g of blood at a concentration of 0.62 ppm there are 3.5g of lead content
Explanation:
- blood density: 1.06 g/L
- ppm ≡ mg Pb / L blood
⇒ V blood = 6.0E3gblood * L / 1.06gblood = 5660.37 L blood
<u> mass of lead:</u>
⇒ 5660.37 L blood * 0.62 mg Pb / L blood * 0.001 g / mg
⇒ mass = 3.509 g of lead
Answer: It's the anode broski (B)
Explanation: I'm taking the Chem summer course too broski, this was the correct answer. Cheers broski
Explanation:
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Answer:
Explanation:
Given parameters:
number of moles magnesium = 6.80mol
number of moles of chlorine = 13.56mol
To find the complete chemical formula, we should obtain the formula of the compound.
Mg Cl
Number of
moles 6.8 13.56
Dividing
by the smallest 6.8/6.8 13.56/6.8
1 2
The formula of the compound is MgCl₂
This is an ionic compound in which Magnesium loses two electrons that would be gained by Cl atoms requiring just an electron each to complete their octet.
Answer:In regards to writing the formula, we know that magnesium has a charge of 1+ and sulfate, SO4, has a charge of 1-. Sulfate is a polyatomic ion so the charge of the whole thing is (SO4)1-. When you combine them you end up with MgSO4 and the "heptahydrate" is seven water molecules.
Explanation:
