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Alexus [3.1K]
3 years ago
15

Why, when establishing the baseline, are you asked to add 1 ml of water? why add 10 ml of sulfuric acid to your peroxide samples

if there was no catalase to denature? please explain!?
Chemistry
1 answer:
Fed [463]3 years ago
4 0

Hydrogen chloride or most commonly known as hydrochloric acid and muriatic acid is a diatomic compound that consists of hydrogen and chlorine. It is prepared industrially by the combustion of hydrogen, H2, in chlorine, Cl2. H2 + Cl2 -> 2HCl. There are also many metallic chlorides that release hydrogen chloride gas, HCl, when warmed with concentrated sulfuric acid, H2SO4. Mostly, it is prepared by heating it with sulfuric acid and sodium chloride. The reaction is NaCl + H2SO4 -> HCl + NaHSO4. Adding sulfuric acid enables the reaction to proceed further and it acts as a catalyst in the reaction.

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For the neutralization reaction involving hno3 and ca(oh)2, how many liters of 1. 55 m hno3 are needed to react with 45. 8 ml of
Agata [3.3K]

For the neutralization reaction involving HNO₃ and Ca(OH)₂, liters of 1.55 M HNO₃ are needed to react with 45.8 ml of a 4.66 m Ca(OH)₂ solution is 0.270 L.

<h3>What is neutralization reaction?</h3>

Those reactions in which acids and bases will combine with each other for the formation of water molecule and salt, is known as neutralization reaction.

Given chemical reaction is:

2HNO₃ + Ca(OH)₂ → 2H₂O + Ca(NO₃)₂

Moles (n) of Ca(OH)₂ will be calculated by using the below formula:
M = n/V, where

M = molarity = 4.66M

V = volume = 45.8 mL = 0.045 L

n = (4.66)(0.045) = 0.2097 mol

From the stoichiometry of the reaction,

1 mole of Ca(OH)₂ = reacts with 2 moles of HNO₃

0.2097 mole of Ca(OH)₂ = reacts with 2×0.2097=0.419 moles of HNO₃

Again by using the molarity equation volume will be calculated for HNO₃ as:

V = (0.419) / (1.55) = 0.270 L

Hence required volume of HNO₃ is 0.270 L.

To know more about neutralization reaction, visit the below link:

brainly.com/question/23008798

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