121•7=847
847-703= 144
A=144
Square-root of two multiplied by the cube-root of 2
=sqrt(2)*(2)^(1/3)
=2^(1/2)*2^(1/3)
=2^(1/2+1/3) multiplication rule of exponents
=2^((3+2)/6)
=2^(5/6)
=(2^5)^(1/6).........sixth root of 2^5
=(32)^(1/6) ............sixth root of 32.
C) p ≤ 78
I got 78 by subtracting 118 by 40. Since we know the maximum is 118 we can't get any higher than 78 so it has to be equal or less than.
Answer:
2x(4x + 3)
Step-by-step explanation:
8x^2 + 6
So the common terms that can be taken out are x and 2
Hence, it can be written as 2x (4x + 3)
Your work looks good, the ages will be
