I'm not sure what this question means exactly, maybe the principals goal is unrealistic?
Let's solve your equation step-by-step.
2
x
=
12
Step 1: Divide both sides by 2.
2
x
2
=
12
2
x
=
6
Answer:
x
=
6
Answer:
A,C,F
Step-by-step explanation:
Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius
to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=

points (-3,2) and (1,5)
D=

D=

D=

D=

D=5
center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1
the point (-7,5) and (7,-1) lie on this circle
radius=5 units
the points (-7,5) and (-7,1) lie on this circle
The answers for the exercise shown in the figure attached above, are shown
-The Compound inequality for the solution 1 is:
-2(x+1)≥-4 or 4x-7≥5
x≥1
x≥3
-The Compound inequality for the solution 2 is:
-6≤2x-8≤-2
1≤x≤3
-The Compound inequality for the solution 3 is:
3x-4≥5 or -5x+17≤12
x≥3
x<1