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Temka [501]
3 years ago
15

If a man hold his breath for three minutes and dies because of it what is that called

Mathematics
1 answer:
miss Akunina [59]3 years ago
6 0

Answer:

Holding your breath is called static Apnea and a common person can't hold their breath for long. If a person holds their breath for long and dies because of it, it may be called lack of breath or lack of respiration.

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At 2:00pm a car's speedometer reads 20mph, and at 2:10pm it reads 30mph.
Dmitry [639]

Over this 10-minute interval, the car's average acceleration is

\dfrac{30\,\mathrm{mph}-20\,\mathrm{mph}}{10\,\mathrm{min}}=\dfrac{10\,\mathrm{mph}}{\frac16\,\mathrm h}=60\dfrac{\rm mi}{\mathrm h^2}

The MVT says that at some point during this 10-minute interval, the car must have had an acceleration of 60 mi/h^2.

6 0
3 years ago
A machine is designed to fill toothpaste tubes, on an average, with 5.8 ounces of toothpaste. The manufacturer does not want any
pochemuha

The correct hypothesis that can be set up for this test is given as

H0: mu = 5.8

Ha: mu ≠ 5.8

<h3>What is a statistical hypothesis?</h3>

This is the method of inference that is made in a statistical testing in order to know if the dat available is able to support the claims that have been made.

What the manufacturer wants to know is the average filling of the machine. If it is within 5.8 or not.

Read more on hypothesis here:

brainly.com/question/11555274

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4 0
2 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
A model builder has 30 pieces of balsa wood in a box. Four pieces are 15 inches long, 10 pieces are 12 inches long, and the rest
VladimirAG [237]
There is about a 16.5% chance to pull an 8-inch piece, this is theoretical probability though. <span />
5 0
3 years ago
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Which equation would have real zero(s) corresponding to the x-intercept(s) of the graph below?
Valentin [98]

Answer:

A on Edg2020

Step-by-step explanation:

6 0
3 years ago
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