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inn [45]
2 years ago
7

How to factor the function: f(x)= 2x^3+14x^2+24x

Mathematics
1 answer:
larisa [96]2 years ago
5 0
We first an take out a factor of 2x
2x(x^2 + 7x + 12)
Then factor inside the brackets
2x(x+4)(x+3)
You might be interested in
First derivative of 5x
Mashutka [201]
The first derivative is 5
4 0
3 years ago
What's 12+ 4X when X= 1 1/2
zaharov [31]
Your answer would be 18 because 1 1/2 x 4 =6. So 6 =12 is 18
<span />
5 0
3 years ago
Read 2 more answers
Which value is equivalent to<br> 3/11?<br> OA A. 0.27<br> O<br> B. 0.27<br> OC<br> C. 3.6<br> OD. 3.
Sladkaya [172]

Answer:

0.27 repeating.

Step-by-step explanation:

So to solve this we just have to use division.

1 clearly doesnt go into 3 at least one time, so we can add a decimal point and add a 0 to make it 30.

11 goes into 30 2 times, so we have:

0.2

and 30-22=8

So we can add another 0 and make it 80.

Then 11 goes into 80 7 times. So we have:

0.27

and 80-77=3

So again, add the 0, we have 30.

11 goes into 30 2 times, so:

0.272

and 30-22=8

Add another 0 we get 80.

11 goes into 80 7 times.

So finally, we have:

0.2727.

This is a repeating decimal.

This can be shown as:

0.<u>27</u>

So this is your answer!

I was a bit confused with which one it was on your answer key, but knowing that it is 0.<u>27</u> I am guessing you can chose!

Hope this helps!

4 0
2 years ago
I need help with this
SVETLANKA909090 [29]

Answer:

The answer is 0.675

Step-by-step explanation:

If you were going to ask Brainly, you could have easily just used a calculator lol

4 0
3 years ago
In how many ways can a committee of four men and four woman be formed from a group of seven men and eleven women?
-Dominant- [34]
Choosing 4 men from seven can be done in 7C4 = 35 ways
(There are 7 to choose from then 6 and 5 and 4 = 7 x 6 x 5 x 4
but we don’t want them in order so we need to divide by 4! = 4 x 3 x 2 x 1)
Similarly choosing 4 women from 11 can be done in 11C4 = 330 ways.

Total number of ways to choose 4 men and 4 women = 35 x 330 = 11550
3 0
1 year ago
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